NEET Chemistry Questions: D & F Block Elements

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In 3d series of transition element atomic radii remains same from Cr to Cu because




No explanation available.
Which elements have low ionisation enthalpy as compare to their neighbour element in first transition element ?




No explanation available.
Thermal stability of transition metal elements depends upon which of the following ?




The thermal stability of transition metal elements is influenced by the magnitude of their ionization enthalpy. Elements with higher ionization enthalpies tend to have more stable compounds because the energy required to remove an electron is greater, making it harder for the element to participate in reactions that would lead to decomposition.
What is colour of aqueous solution of $ [ Ni (H_2 O) _6 ] ^ {2t } $




The color of an aqueous solution of $[Ni(H_2O)_6]^{2+}$ is green. This is due to the d-d transitions of the nickel(II) ion in the octahedral crystal field created by the water ligands. The specific wavelengths of light absorbed and emitted result in the observed green color.
What is colour of aqueous solution of $ [Co(NH_3)_6]^{3+} $




The complex ion $[Co(NH_3)_6]^{3+}$ is known to have a yellowish-orange color in its aqueous solution. This is due to the electronic transitions within the d-orbitals of the cobalt ion influenced by the ligand field created by the ammonia molecules.
Which of the following metal ions have pink colour ?




$Co^{2+}$ ions typically exhibit a pink color in their hydrated form, and $Mn^{2+}$ ions are also known to be pale pink. Therefore, the correct option is $Co^{2+}$ and $Mn^{2+}$, which match the description of having a pink color.
Which of the following metal ion is purple ?




$Ti^{3+}$ ions are known to exhibit a purple color. This is due to the specific electronic transitions within the d-orbitals of the titanium ion, which absorb certain wavelengths of light and reflect the purple color.
Match column-A and B Column _A 1 . $ V^ {4+} $ 2 . $ Ti ^ {3+} $ 3 . Ti ^{4+} $ 4 . Mn ^ {2+} $ Column_B A. Colourless B. Pink C.Purple D. Blue E. Violet




No explanation available.
Match column-A and B Column _A 1. $ NiCl_2 .6H_2 O $ 2. $ Co(NO_3)_2 . 6H_2 O $ 3. $ FeCl_3 $ 4. $ CuSO_4 . 5 H_2 O $ Column_B A. Pink B. Colourless C. Blue D. Green E. Yellow




The color of hydrated salts is due to the d-d transitions of the metal ions in the crystal field created by the water molecules. Here are the correct matches: 1. $NiCl_2 ullet 6H_2O$ is green 2. $Co(NO_3)_2 ullet 6H_2O$ is pink 3. $FeCl_3$ is yellow 4. $CuSO_4 ullet 5H_2O$ is blue Therefore, the correct matching is 1-d, 2-a, 3-e, 4-c.
Which catalyst is used to prepare $SO_3$ from $SO_2$ in contact process of production of $ H_2SO_4$ ?




In the contact process for the production of sulfuric acid, $V_2O_5$ (vanadium pentoxide) is used as the catalyst to convert $SO_2$ to $SO_3$. The reaction is as follows: $$2SO_2 + O_2 ightarrow 2SO_3$$ This reaction is catalyzed by $V_2O_5$.
Which of the following transtion metal ion has magnetic moment 3.87 BM ?




No explanation available.
In which of the following compound of trantion metal ion has 4.90 BM magnetic momentum?




The magnetic moment can be calculated using the same formula: $$ ext{Magnetic Moment} ( ext{BM}) = ext{n(n+2)} $$, where 'n' is the number of unpaired electrons. For $Fe^{2+}$ in $FeSO_4$, which has an electron configuration of [Ar] 3d^6, there are 4 unpaired electrons. Therefore, the magnetic moment is approximately 4.90 BM.
Which of the following sentence is not suitable for the capacity of transition metal to form complex compounds ?




Transition metal ions are known to form complex compounds due to their small size, high nuclear charge, and the presence of different oxidation states. However, the statement 'Co-ordination covalent bond is not directional' is incorrect. Co-ordination bonds are indeed directional, as the geometry of the complex depends on the spatial arrangement of the ligands around the central metal ion.
Which of the following rules to prepare alloys should be obey ?




To prepare alloys, the difference in atomic radii of the constituent elements should be less than 15%. This rule helps ensure that the alloy has a homogeneous structure and maintains good mechanical properties. If the atomic radii difference is too large, it can lead to structural inconsistencies and weaken the alloy.
What is the difference in atomic radii of two metallic elements to prepare alloys ?




No explanation available.