NEET Chemistry Questions: D & F Block Elements

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Which of the following solid salt on heating with K2Cr2O7 and Conc. H2SO4 orange,red vapours are evolved which turn aquous NaOH solution yellow?





(b) NaCl(s) + K2Cr2O7 + H2SO4 (few drops)reactionNon redoxCrO2Cl2+H2O

CrO2Cl2 + OH-(aq.)CrO4(aq)2-+Cl-+2H2O

Fe is made passive by :





(c) 

 

Formation of a thin layer of oxide upon the surface of metal, which protects the inner surface of metal to come in direct contact of air or other chemicals for reaction.

The iron salt used in blue prints is:





No explanation available.

Which has highest melting point?





 

M.p 2617 Molybdenum Mo
1857 Chromium Cr
1535 Iron Fe
1083 Copper Cu

 

 

 

The colour of KMnO4 is due to





In KMnO4, Mn has no d-electron and colour is due to charge transfer spectra

Which of the following element does not show the variable oxidation state?





Pseudo transition element have 10 electro in d subshell , so cannot lose electron from d subshell.

With F highest stable oxidation state of Mn is





 

MnF4

Mn has 2 s electrons and five d. The s electrons can be unpaired to the 4p orbital..But almost three d orbitals can be used to form sigma bonds

Why?..

dz2 and dx2-y2 are the only two orbitals axially oriented and suited for head on sigma overlap…the other orbitals ar oriented in between axes . So they can only form pi bonds.

However…atmoat 1 non axial d orbital can be used so that just enough limiting stability is present in the molecule so formed as the involvement of Pi character in a sigma bond weakens it.

Cr2O72-+XH+Cr3++H2O + oxidized product of X, X in the above reaction cannot be





SO42- can't be oxidised because S has highest oxidation state i.e. +6

The basic oxide is:





Lesser is the oxidation state of Cr in oxide, more is the basic nature.

The pair having similar magnetic moment is





Mn2+ and Fe3+both have 5 unpaired electrons. So, they have same magnetic moment

Lanthanoid which is radioactive is





In lanthanoid only Promethium (Pm) 61 is radioactive

Which of the following is most basic?





In lanthenoid series, as we move from left to right then basic nature of hydroxide decrease.

Which is colourless in water?





Sc3+ has no unpaird electron. Hence it is colourless.

The main reason for a larger number of oxidation states exhibited by the actinoids than the corresponding lanthanoids is





 

Actinoids show different oxidation states such as +2, +3, +4, +5, +6 and +7. However +3 oxidation state is most common among all the actinoids.

The wide range of oxidation states of actinoids is attributed to the fact that the 5f, 6d and 7s energy levels are of comparable energies.

Therefore, all these three subshells can participate.

CrO42- and MnO4- are strong yellow and intense purple  respectively in aqueous solution The darkening of colour is due to





charge-transfer complex (CT complex) or electron-donor-acceptor complex is an association of two or more molecules, or of different parts of one large molecule, in which a fraction of electronic charge is transferred between the molecular entities. The resulting electrostatic attraction provides a stabilizing force for the molecular complex. The source molecule from which the charge is transferred is called the electron donor and the receiving species is called the electron acceptor.

The nature of the attraction in a charge-transfer complex is not a stable chemical bond, and is thus much weaker than covalent forces. Many such complexes can undergo an electronic transition into an excited electronic state. The excitation energy of this transition occurs very frequently in the visible region of the electromagnetic spectrum, which produces the characteristic intense color for these complexes. These optical absorption bands are often referred to as charge-transfer bands (CT bands). Optical spectroscopy is a powerful technique to characterize charge-transfer bands.

Charge-transfer complexes exist in many types of molecules, inorganic as well as organic, and in solids, liquids, and solutions. A well-known example is the complex formed by iodine when combined with starch, which exhibits an intense blue charge-transfer band.

In inorganic chemistry, most charge-transfer complexes involve electron transfer between metal atoms and ligands. The charge-transfer bands of transition metal complexes result from shift of charge density between molecular orbitals (MO) that are predominantly metal in character and those that are predominantly ligand in character. If the transfer occurs from the MO with ligand-like character to the metal-like one, the complex is called a ligand-to-metal charge-transfer (LMCT) complex. If the electronic charge shifts from the MO with metal-like character to the ligand-like one, the complex is called a metal-to-ligand charge-transfer (MLCT) complex. Thus, a MLCT results in oxidation of the metal center, whereas a LMCT results in the reduction of the metal center. Resonance Raman spectroscopy[1] is also a powerful technique to assign and characterize charge-transfer bands in these complexes.