NEET Physics Questions: Motion in a Straight Line
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The graph of displacement v/s time is
Its corresponding velocity-time graph will be
S vs.t is parabola
So V vs. t must be line and at t = 0 ds/dt>0
So option 1 is correct graph.
A thief was planning to rob the minister's house located 100m away from his home.he started moving with a constant speed of 3m/s.on seeing a police jeep at exact mid way he started running back to his home with a speed of 9 m/s. the average speed and average velocity repectively in m/s is
average speed is the ratio of total distance travelled to the total time taken .since initial and final position is the same average velocity is zero
A branch of physics dealing with motion without considering its causes is known as ....
The branch of physics dealing with motion without considering its causes is known as kinematics. Kinematics focuses on describing how objects move, using concepts such as displacement, velocity, and acceleration, without analyzing the forces or energies involved in causing the motion.
To locate the position of the particle we need ...
To locate the position of a particle, we need a frame of reference. A frame of reference is a coordinate system that allows us to specify the position of a particle in space by giving its coordinates relative to some origin.
A car goes from one end to the other end of a semicircular path of diameter βdβ. Find the ratio between path legth and displacement.
The path length of a car moving along a semicircular path of diameter 'd' is equal to half the circumference of a circle, which is $\pi d / 2$. The displacement is the straight line distance between the start and end points, which is 'd'. Therefore, the ratio between the path length and displacement is $(\pi d / 2) / d = \pi / 2$.
The ratio of pathlength and the respective time interval is
The ratio of path length to the respective time interval is called mean speed. Mean speed is defined as the total distance traveled divided by the total time taken.
A car covers one third part of its straight path with speed $V_1$ and the rest with speed $V_2$. What is its average speed ?
No explanation available.
Rohit completes a semicircular path of radius R in 10 seconds. Calculate average speed and average velocity in $ms^{β1}$.
To calculate the average speed and average velocity for Rohit completing a semicircular path of radius R in 10 seconds, we start with the average speed. The average speed is the total distance traveled divided by the total time taken. For a semicircle, the distance is half the circumference of a full circle, which is $ rac{1}{2} imes 2 ext{Ο}R = ext{Ο}R$. Therefore, the average speed is $$ ext{Average speed} = rac{ ext{Ο}R}{10}.$$ For the average velocity, we consider the straight-line displacement from the start to the end of the semicircle, which is the diameter of the circle, or $2R$. Therefore, the average velocity is $$ ext{Average velocity} = rac{2R}{10}.$$ This matches the option 'o3'.
A particle moves 4m in the south direction. Then it moves 3m in the west direction. The time taken by the particle is 2 second. What is the ratio between average speed and average velocity ?
No explanation available.
What does the speedometer measure kept in motorbike ?
A speedometer measures the instantaneous speed of a vehicle. Instantaneous speed is the speed of an object at a particular moment in time. It does not measure average speed or velocity. Hence, the correct option is o3: instantaneous speed.
A particle is thrown in upward direction with initial velocity $V_0$. It crosses point P at height h at time $t_1$ and $t_2$ so $t_1 t_2$ =
$ h = V_0 t - {1 \over 2 } gt^2 $
$ \therefore {1 \over 2 } gt^2 - V_0 t + h = 0 $
$ \therefore t^2 + { 2V_0 \over g } - { 2h \over g } = 0 $
There are two real values of t .
Slope of the velocity-time graph gives............ of a moving body.
The slope of a velocity-time graph represents the acceleration of the moving body. This is because acceleration is defined as the rate of change of velocity with respect to time. Therefore, the slope of the velocity-time graph is the acceleration. Hence, the correct option is o2: acceleration.
The intercept of the velocity-time graph on the velocity axis gives.
The intercept of the velocity-time graph on the velocity axis represents the velocity when time is zero. This is defined as the initial velocity ( ext{u}). Mathematically, it is the value of the velocity at the point where the time ( ext{t}) is zero.
In a uniformly accelerated motion the slope of velocity - time graph gives ....
In a uniformly accelerated motion, the slope of the velocity-time graph gives the acceleration ( ext{a}). This is because acceleration is defined as the rate of change of velocity with respect to time, which is represented by the slope of the velocity-time graph.
The area covered by the curve of V β t graph and time axis is equal to magnitude of ..
The area covered by the curve of the velocity-time (V-t) graph and the time axis represents the displacement ( ext{s}). This is because displacement is the integral of velocity with respect to time, which geometrically corresponds to the area under the velocity-time graph.