NEET Questions - Physics - Oscillations and Waves

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The distance travelled by a particle performing S.H.M. during time interval equal to its periodic time is ……..

A
2A
4A
Zero

A person standing in a stationary lift measures the periodic time of a simple pendulum inside the lift to be equal to T. Now, if the lift moves along the vertically upward direction withan acceleration of g/3 ,then the periodic time of the lift will now be ………

$ \sqrt 3 T $
$ { \sqrt 3 \over 2 } T $
$ { T \over 3 } $
$ { T \over \sqrt 3 } $

If the equation for displacement of two particles executing S.H.M. is given by $y_1 = 2Sin(10t+è)$ and $y_2 = 3Cos10t$ respectively, then the phase difference between the velocity of two particles will be ………..

-e
e
$ \theta - { \pi \over 2 } $
$ \theta + { \pi \over 2 } $

If the maximum velocity of two springs ( both has same mass ) executing S.H.M. and having force constants $ k_1 and k_2 $ respectively are same, then the ratio of their amplitudes will be

$ { k_1 \over k_2 } $
$ { k_2 \over k_1} $
$ \sqrt { k_1 \over k_2 } $
$ \sqrt { k_2 \over k_1 } $

The bob of a simple pendulum having length ‘ l’ is displaced from its equilibrium position by an angle of è and released. If the velocity of the bob, while passing through its equilibrium position is v, then v =

$ \sqrt {2gl (1 - cos \theta) } $
$ \sqrt {2gl (1 + sin \theta) } $
$ \sqrt {2gl (1 - sin \theta) } $
$ \sqrt {2gl (1 + cos \theta) } $

If 1/4 of a spring having length l is cutoff, then what will be the spring constant of remaining part?

k
4k
4k/3
3k/4

The amplitude for a S.H.M. given by the equation x = 3Sin3pt + 4Cos3pt is ………m.

5
7
4
3

When an elastic spring is given a displacement of 10mm, it gains an potential energy equal to U. If this spring is given an additional displacement of 10 mm, then its potential energy will be

U
2U
4U
U/4

The increase in periodic time of a simple pendulum executing S.H.M. is............ when its length is increased by $ 21 \% $ .

$ 42 \% $
$ 10 \% $
$ 11 \% $
$ 21 \% $

A particle executing S.H.M. has an amplitude A and periodic time T. The minimum time required by the particle to get displaced by $ A / \sqrt 2 $ from its equilibrium position is ...................s.

T
T/4
T/8
T / 16

If a body having mass M is suspended from the free ends of two springs A and B, their periodic time are found to be $T_1$ and $T_2$ respectively. If both these springs are now connected in series and if the same mass is suspended from the free end, then the periodic time is found to be T. Therefore …………..

$ T = T_1 + T_2 $
$ { 1 \over T } = { 1 \over T_1 } + {1 \over T_2 } $
$ T^2 = T_1^2 + T_2^2 $
$ { 1 \over T^2 } = { 1 \over T_1^2 } + {1 \over T_2^2 } $

The displacement of a S.H.O. is given by the equation $ x = A cos ( ut + { \pi \over 8 } ) $ . At what time will it attain Maximum velocity?

$ 3 \pi \over 8 \omega $
$ 8 \pi \over 3 \omega $
$ 3 \pi \over 16 \omega $
$ \pi \over 16 \omega $

At what position will the potential energy of a S.H.O. become equal to one third its kinetic energy?

$ \pm { A \over 2 } $
$ \pm { A \over \sqrt 2 } $
$ \pm { A \over \sqrt 3 } $
$ \pm \sqrt 3 A $

For particles A and B executing S.H.M., the equation for displacement is given by $y_1 = 0.1Sin(100t+p/3) $ and $y_2 = 0.1Cospt $ respectively. The phase difference between velocity of particle A with respect to that of B is …………

$ - { \pi \over 3 } $
$ { \pi \over 6 } $
$ - { \pi \over 6 } $
$ { \pi \over 3 } $

The periodic time of a simple pendulum is $T_1$. Now if the point of suspension of this pendulum starts moving along the vertical direction according to the equation $y = kt^2$, the periodic time of the pendulum becomes $T_2$ . Therefore, $ {T_1 ^2 \over T_2^2 } = .........( k =1 m/s^2 and g = 10 m/s^2 ) $

6/5
5/6
4/5
1

NEET Physics Questions: Oscillations and Waves