NEET Physics Questions: Thermodynamics

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Two liquids of equal volume are throughly mixed. If their specific heat are $C_1, C_2$, temperatures $ \theta_1, \theta_ 2$ and densities $d_1, d_2$ respectively. What is the final temperature of the mixture ?




$ mC_1 ( \theta_1 - \theta_e ) = m C_2 ( \theta_e - \theta_2 ) $ $ Vd_1C_1 ( \theta_1 - \theta_e) = Vd_2 C_2( \theta_e - \theta_2) $ $ \Rightarrow d_1 c_1 \theta_1 -(d_1c_1) \theta_e = (d_2 c_2) \theta_e - d_2 c_2 \theta_2 $
Amount of heat required to raise the temprature of a body through 1k is called it is




$ \theta = m.c \triangle \theta $ ; if $ \triangle \theta = 1k $ then $ \theta = mc Thermal capacity$
Assertion & Reason Read the assertion and reason carefully to mark the correct option out of the option given below. Assertion : Melting of solid causes no change in internal energy. Reason :Latent heat is the heat required melt a unit mass of solid.




Melting is associated with increasing of internal energy without change in temperature in view of the reason being correct the amount of heat absorbed or given out during change of state is expressed where m is the mass of the substances and L is the latent heat of the substance.
A difference of temperature of $25 ^\circ C $ is equivalent to a difference of




$ { \triangle C \over 100 ^\circ } = { \triangle F \over 180 ^\circ } $ $ \therefore {25 \over 100} = { \triangle F \over 180 } $
What is the value of absolute temperature on the Celsius Scale ?




$ T = 273.15 + t^\circ C $ $ 0 = 273.15 + t^\circ C $
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The temperature of a substance increases by $ 27 ^\circ $ What is the value of this increase of Kelvin scale ?




equal
At Which temperature the density of water is maximum?




$ 4 ^\circ $
The temperature on celsius scale is $ 25 ^\circ C $ . What is the corresponding temperature on the Fahrenheit Scale?




$ { c \over 5 } = {F -32 \over 9 } $
The temperature of a body on Kelvin Scale is found to be x.K.when it is measured by Fahrenhit thesmometes. it is found to be $x^0F$ , then the value of x is .




$ {F -32 \over 9 } = { K -273 \over 5 } $
A Centigrade and a Fahrenhit thesmometes are dipped in boiling wates-The wates temperature is lowered until the Farenhit thesmometes registered $140 ^\circ $ what is the fall in thrmometers




$ { \triangle Tc \over 100 } = { \triangle TF \over 180 } $ $ { \triangle Tc \over 100 } \triangle TC = 40 ^ \circ C $
A uniform metal rod is used as a bas pendulum. If the room temperature rises by $ 10 ^\circ C $ and the efficient of line as expansion of the metal ofthe rod is, $ 2 \times 10^{-6} 0_c^{-1} $ what will have percentage increase




$ { \triangle T \over T } = { 1 \over 2} 2 \triangle 0 = { 1 \over 2} \times 2 \times 10 ^ {-6} \times 10 = 10 ^ {-5} $ $ \% in increase = { \triangle T \over T } \times 100 = 10 ^ {-5} \times 100 = 1 \times 10 ^ {-3} \% $
A gas expands from 1 litre to 3 litre at atmospheric pressure. The work done by the gas is about




$ W = p \triangle V $
Each molecule of a gas has f degrees of freedom. The radio $ { C_P \over C_V} = \gamma $ for the gas is




$C_p = \left( { f \over 2 } + 1 \right) R, C_v = {f \over 2} R $ $ { C_p \over C_v }= { \left( { f \over 2 } + 1 \right) R \over { f \over 2} R } = { {f \over 2} + 1 \over { f \over 2} } = { f+2 \over f} = 1 + { 2 \over f } $
If the ratio of specific heat of a gas at Consgant pressure to that at constant volume is $ \gamma $ , the Change in internal energy of the mass of gas, when the volume changes from V to 2V at Constant Pressure p, is




$ \triangle u = { P (V_2 - V_1) \over \gamma _1 } = { PV \over \gamma - 1 } $
The change in internal energy, when a gas is cooled from $ 927 ^\circ to 27 ^\circ C $




$ U \alpha T { u_1 \over u_2} = { T_1 \over T_2} $ $ \therefore { u_1 - u_2 \over u_2} = {T_1 - T_2 \over T_2} $