Chemical equilibrium AIIMS 2017
Asked by Divyank Singh Tiwari · 5 years ago
Doubt
2 Answers
Total pressure=1atm=10^5pa Vol of A=20% So vol of A2=80% Partial pressure of A= 0.2×10^5 Partial pressure of A2=0.8×10^5 Kp of rxn=[PA]^2/[Pa2] =[0.2×10^5]2/[0.8×10^5] =0.5×10^4 Kp=5×10^3
Metla Lakshmi ratna Sri · 5 years ago
Solution
Aditi Ghuge · 5 years ago
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