Chemical kinetics
Asked by SAURAV BHADANI · 5 years ago
The rate of first order reaction is 0.04 mol L s at 10seconds and 0.03 mol L s at 20seconds after intiation of reaction .The half life period of reaction is
1 Answer
The rate law expression for the first order reaction is  =K×[A]. Substitute values in the above expression. 0.04=K[A]10​......(1) 0.03=K[A]20​......(2) Divide equation (1) by equation (2). [A]20​[A]10​​=0.030.04​=34​ At 10 min, the expression for the rate constant will be t=K2.303​log[A]20​[A]10​​. 10=K2.303​log34​. Hence, the rate constant K=102.303​log34​=0.0288min−1
The half life period is t1/2​=K0.693​=0.02880.693​=24.06min−1
Aditi Ghuge · 5 years ago
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