Chemistry

there is one peroxy linkage S−O−O−S. Hence two of the eight oxygen atoms have -1 oxidation state and rest 6 have -2 oxidation state. Let the total oxidation state of S be x

then 2×1+x+6×(−2)+2×(−1)=0

or 2+x−12−2=0

x=+12

Sum of oxidation state of both S is x i.e. 12 in H2​S2​O8​.