Asked by Ayushi Sneha · 4 years ago
If the equation for the displacement of a particle moving on a circular path is given by 3t^2+2t where is in the radian and t in seconds then the angular velocity of the particle after 3 s from its start is
Solution
Aditi Ghuge · 4 years ago
Displacement (thetha)=3t^2+2t Angular velocity=Displacement ÷time Angular velocity =3×2t+2 =6t+2 (time=3s) =6×3+2 =18+2 =20rad/sec
SADAF NAYAB · 4 years ago
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