Deriving Electric Field Using Gauss's Law

Asked by Mahek A · 2 years ago

How can we derive the electric field of a uniformly charged sphere using Gauss's Law?

1 Answer

To derive the electric field of a uniformly charged sphere using Gauss's Law, follow these steps:

  1. Consider a sphere of radius R with a uniform charge distribution and total charge Q.
  2. To find the electric field outside the sphere (at a distance r where r > R), choose a Gaussian surface that is a sphere of radius r centered at the same point as the charged sphere.
  3. By symmetry, the electric field E will be radial and have the same magnitude at every point on the Gaussian surface.
  4. According to Gauss's Law: ∮ E · dA = Q_enclosed / ε₀
  5. Here, Q_enclosed is Q (the total charge of the sphere), and dA is the differential area element of the Gaussian surface.
  6. The electric flux ∮ E · dA becomes E · 4πr² (since the surface area of a sphere is 4πr²).
  7. Therefore, E · 4πr² = Q / ε₀.
  8. Solving for E, we get E = Q / (4πr²ε₀).
  9. Thus, the electric field outside a uniformly charged sphere is E = Q / (4πr²ε₀), and it behaves like the field of a point charge.

NEET Faculty · 2 years ago

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