Mechanism of Hoffmann Bromamide Reaction

Asked by Sultanah Fatimah · 2 years ago

Can someone explain the mechanism of the Hoffmann Bromamide reaction in detail?

1 Answer

The Hoffmann Bromamide reaction is a chemical reaction that converts an amide to a primary amine with one fewer carbon atom. The general reaction involves the use of bromine (Br2) and a strong base like sodium hydroxide (NaOH).

Steps involved in the mechanism:

  1. Bromination: The amide reacts with bromine to form an N-bromoamide intermediate.
  2. Deprotonation: The strong base (NaOH) deprotonates the N-bromoamide to form a bromoamide anion.
  3. Rearrangement: The bromoamide anion undergoes a rearrangement where the carbonyl carbon gets bonded to nitrogen, releasing a bromide ion and forming an isocyanate intermediate.
  4. Hydrolysis: The isocyanate intermediate reacts with water to form a carbamic acid, which then decomposes to yield a primary amine and carbon dioxide (CO2).

The overall reaction can be summarized as:

RCONH2 + Br2 + 4NaOH → RNH2 + Na2CO3 + 2NaBr + 2H2O

NEET Faculty · 2 years ago

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