Some basic concepts of chemistry
Asked by Ravula Tulasi Naga Pavan Kumar · 2 years ago
A mixture contains Na2CO3 and NaHCO3 and wt. of mixture is 10gm. Mixture on heating liberates 56ml of CO2 at S.T.P, wt of Na2CO3 in mixture is
1 Answer
Weight Calculation of Na2CO3 in Mixture
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Calculate the amount of CO2 released:
We know that 56 mL of CO2 is released when the mixture is heated. This is equivalent to 0.0025 moles of CO2 at standard temperature and pressure.
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Understand the reaction:
Heating sodium bicarbonate (NaHCO3) produces sodium carbonate (Na2CO3), water, and CO2. From the chemical equation, we see that 2 moles of NaHCO3 produce 1 mole of CO2.
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Find the amount of sodium bicarbonate:
Since 2 moles of NaHCO3 produce 1 mole of CO2, 0.005 moles of NaHCO3 are needed to produce 0.0025 moles of CO2.
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Calculate the mass of sodium bicarbonate:
The mass of 0.005 moles of NaHCO3 is 0.42 grams.
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Determine the mass of sodium carbonate:
The total mass of the mixture is 10 grams. If 0.42 grams is NaHCO3, the rest of the mixture (10 grams - 0.42 grams) is Na2CO3.
We know that 56 mL of CO2 is released when the mixture is heated. This is equivalent to 0.0025 moles of CO2 at standard temperature and pressure.
Heating sodium bicarbonate (NaHCO3) produces sodium carbonate (Na2CO3), water, and CO2. From the chemical equation, we see that 2 moles of NaHCO3 produce 1 mole of CO2.
Since 2 moles of NaHCO3 produce 1 mole of CO2, 0.005 moles of NaHCO3 are needed to produce 0.0025 moles of CO2.
The mass of 0.005 moles of NaHCO3 is 0.42 grams.
The total mass of the mixture is 10 grams. If 0.42 grams is NaHCO3, the rest of the mixture (10 grams - 0.42 grams) is Na2CO3.
Conclusion: The weight of Na2CO3 in the mixture is 9.58 grams.
Hope this helps.
Sam Faculty · 2 years ago
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