Titration
Asked by Shubha Murthy · 5 years ago
It takes 26.23 mL of a 1.008 M NaOH solution to neutralize a solution of 5 g of an unknown monoprotic acid in 150.2 mL of solution. What is the molecular weight of the unknown
1 Answer
Pehle N1V1=N2V2 Se N2 Ki normality nikal lo, phir ise use karna N2=wt1000/eqwtv(ml), yaha se eq wt nikal lo , and molar mass=eq wt*n factor, n factor is given there 1(monoprotic acid)
Dhiraj Thakur · 5 years ago
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