Chemistry MCQs for NEET — Practice Questions with Answers

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I. Transition metals are characterised by variable oxidation state II. Elements of IB & IIB are transition elements

III. Elements of gp1 exhibit only +1 O.S

IV. Group 17 contains only gases

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Choose correct option I. The ionisation enthalpy of Be > B II. d–Block elements are known as representative elements III. Palladium is the only element of fifth period that has no electron in fifth energy level IV. The second ionisation enthalpy of Al is greater than that of Mg V. Among Li, Be, B ,C N ; Li has least value of electron gain enthalpy

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Choose correct option I. O.S of ‘O’ in $OF_2$ is –2 II. Ionisation enthalpy is the minimum amount of energy required to remove an electron from an atom III. Screening effect : it is the attraction of electron towards the nuclear IV. Half filled orbitals are more stable half fully filled orbitals

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Match the following Set A

  1. Strongest reductant
  2. Fully filled d–orbital
  3. Noble metal
  4. Actinide Set B p) silver q) Berkelium r) Copper s) Iodide ion t) Sodium ion
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Match the following Set A 1. Osmium 2. Lead 3. Tungsten 4. Caesium Set B p) Hardest metal electric q) poor conductor of current r) largest size s) most reactive solid matter t) highest oxidation state

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Set A

  1. Br
  2. Ba
  3. Se
  4. Rb Set B p) Chalcogen q) alkali metal r) alkaline earth metal s) Halogen
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Explanation

Bromine (1) is a halogen (s), Barium (2) is an alkaline earth metal (r), Selenium (3) is a chalcogen (p), and Rubidium (4) is an alkali metal (q). So, the correct match is 1–s, 2–r, 3–p, 4–q.

Match the following Set A

  1. Hg
  2. Carbon (Diamond)
  3. Bromine
  4. Caesium & F Set B p) Liquid non–metal q) reacts very violently r) reaction endothermic s) Liquid metal t) extremely high M.P
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Explanation

Mercury (1) is a liquid metal (s), Carbon in the form of Diamond (2) has an extremely high melting point (t), Bromine (3) is a liquid non-metal (p), and Caesium & Fluorine (4) react very violently (q). Therefore, the correct match is 1–s, 2–t, 3–p, 4–q.

Match the following Set A

  1. Inner transition elements
  2. Transition
  3. Typical element
  4. Representative element Set B p) 3rd period q) s & p Block r) d– Block s) f–Block t) p–Block
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Explanation

Inner transition elements belong to the f-block (s), transition elements are part of the d-block (r), typical elements are found in the 3rd period (p), and representative elements belong to the s & p blocks (q).

Match the following Set A

  1. Be < Al
  2. Aufbau principle
  3. $ns^2 np^{1– 5} $
  4. $ ns^2 np^6 $ Set B p) noble gases q) p–Block r) Diagonal relationship s) Block deciding rule
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Explanation

Beryllium and Aluminum show a diagonal relationship (r), the Aufbau principle represents the rule for filling electrons in orbitals (s), elements with general electronic configuration $ns^2 np^{1– 5}$ belong to the p-block (q), and elements with electronic configuration $ns^2 np^6$ are noble gases (p).

The position of element A, B, C & D are

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