Chemistry MCQs for NEET — Practice Questions with Answers

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At the equilibrium inter-nuclear distance in the $H_2$ molecule, what happens to the potential energy of the system?

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Explanation

The text details the formation of $H_2$: 'At the equilibrium inter-nuclear distance (bond distance) the energy touches a minimum. Any attempt to bring the nuclei still closer results in a sudden increase in energy and consequent destabilization of the molecule.'

Valence Bond Theory is used to explain the formation and geometrical shapes of molecules like:

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Explanation

The text states: 'sp, $sp^2$, $sp^3$ hybridizations of atomic orbitals of Be, B, C, N and O are used to explain the formation and geometrical shapes of molecules like $BeCl_2$, $BCl_3$, $CH_4$, $NH_3$ and $H_2O$.'

What is a limitation of the Lewis approach that Valence Bond Theory addresses?

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Explanation

The text mentions: 'As we know that Lewis approach helps in writing the structure of molecules but it fails to explain the formation of chemical bond. It also does not give any reason for the difference in bond dissociation enthalpies and bond lengths...'

Which of the following is crucial for describing bonding in terms of Valence Bond Theory, but not directly explained by VSEPR theory?

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Explanation

The text states: 'Similarly the VSEPR theory gives the geometry of simple molecules but theoretically, it does not explain them and also it has limited applications. To overcome these limitations the two important theories based on quantum mechanical principles are introduced. These are valence bond (VB) theory and molecular orbital (MO) theory.' VB theory discusses bond formation 'in terms of overlap of orbitals.'

Which of the following properties is NOT a primary reason for the anomalous behavior of second-period elements?

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Explanation

According to the NCERT text, 'The anomalous behaviour is attributed to their small size, large charge/radius ratio and high electronegativity of the elements. In addition, the first member of group has only four valence orbitals (2s and 2p) available for bonding'. Second-period elements do not possess d-orbitals in their valence shell, which is a characteristic of later period elements. The absence of d-orbitals contributes to their anomalous behavior, not their presence.

Lithium and Beryllium differ from other members of their respective groups primarily because they:

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Explanation

The NCERT text states, 'For example, lithium unlike other alkali metals, and beryllium unlike other alkaline earth metals, form compounds with pronounced covalent character; the other members of these groups predominantly form ionic compounds.'

The similarity in behavior between Lithium and Magnesium, and Beryllium and Aluminium, is known as:

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Explanation

The NCERT text explicitly mentions, 'In fact the behaviour of lithium and beryllium is more similar with the second element of the following group i.e., magnesium and aluminium, respectively. This sort of similarity is commonly referred to as diagonal relationship in the periodic properties.'

Why does the first element of a group (like Lithium or Boron) have fewer valence orbitals available for bonding compared to the second element of the same group?

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Explanation

The NCERT text explains, 'In addition, the first member of group has only four valence orbitals (2s and 2p) available for bonding, whereas the second member of the groups have nine valence...'. This is due to the absence of d-orbitals in the second period elements (n=2, so only 2s and 2p orbitals are available).

Which of the following pairs correctly represents elements exhibiting diagonal relationship, as discussed in the context of anomalous properties of second-period elements?

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Explanation

The context states, 'In fact the behaviour of lithium and beryllium is more similar with the second element of the following group i.e., magnesium and aluminium, respectively. This sort of similarity is commonly referred to as diagonal relationship in the periodic properties.' Therefore, Li and Mg exhibit a diagonal relationship.

Consider the following statements regarding the first element of group 13 (Boron) and its anomalous properties: I. Boron forms predominantly ionic compounds. II. Boron has a small size and high electronegativity. III. Boron has only 2s and 2p orbitals available for bonding. Which of the above statements are correct?

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Explanation

The first element of group 13 (Boron) exhibits anomalous properties due to its small size, large charge/radius ratio, and high electronegativity (II). Like other second-period elements, it only has 2s and 2p orbitals for bonding (III), leading to limited valency and orbital expansion. Unlike its heavier congeners which tend to form more ionic compounds, Boron forms compounds with more covalent character due to its high polarizing power. Thus, statement I is incorrect.

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