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What is the IUPAC numerical root for the digit '5' used in naming elements with atomic number greater than 100?
According to Table 3.4 'Notation for IUPAC nomenclature of Elements', the numerical root for the digit '5' is 'pent'.
Which of the following temporary IUPAC names correctly corresponds to its atomic number according to the given nomenclature rules?
For Z=108: un (1), nil (0), oct (8), and 'ium' suffix, making it Unniloctium. Let's check others: Z=109 is Unnilennium (not Ununennium), Z=106 is Unnilhexium (not Unnilseptium), Z=111 is Unununnium (not Ununbium).
The primary reason IUPAC established a systematic temporary nomenclature for elements with Z > 100 was to:
The NCERT text states: 'To avoid such problems, the IUPAC has made recommendation that until a new element’s discovery is proved, and its name is officially recognised, a systematic nomenclature be derived directly from the atomic number of the element...'. This directly addresses the issue of conflicting claims, such as the American and Soviet claims for element 104.
If an element has the temporary IUPAC symbol 'Uuh', what is its atomic number?
From Table 3.4, 'U' stands for 'un' (1), 'u' for 'un' (1), and 'h' for 'hex' (6). Therefore, 'Uuh' corresponds to the atomic number 116. This aligns with Table 3.5 which lists Ununhexium (Uuh) for Z=116.
According to IUPAC recommendations, what suffix is always added at the end of the systematic name for elements with Z > 100?
The NCERT text states: 'The roots are put together in order of digits which make up the atomic number and “ium†is added at the end.' This confirms that '-ium' is the required suffix.
What is the systematic IUPAC name for the element with atomic number 118?
For atomic number 118, the roots are: un (1), un (1), oct (8). Adding the suffix 'ium' gives Ununoctium. This is also confirmed in Table 3.5.
The abbreviation for the numerical root 'tri' in IUPAC nomenclature for elements with Z > 100 is:
As per Table 3.4 'Notation for IUPAC nomenclature of Elements', the abbreviation for 'tri' is 't'.
Which of the following elements has the temporary IUPAC name 'Unnilpentium'?
Un (1) + nil (0) + pent (5) = 105. So, Unnilpentium corresponds to Z=105. This is verified in Table 3.5.
If the official name of an element is Rutherfordium, what was its temporary IUPAC name and atomic number?
From Table 3.5, Rutherfordium is the official name for the element with atomic number 104. Its temporary IUPAC name is Unnilquadium (un (1) + nil (0) + quad (4)).
The element with the temporary IUPAC name 'Unununnium' has the atomic number:
Un (1) + un (1) + un (1) gives the atomic number 111. So, Unununnium is for Z=111. This is consistent with Table 3.5.
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