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Physics MCQs for NEET — Practice Questions with Answers

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An electric kettle has two coils. when onc of them is switched on, the water in the kettle boils in 6 minutes. When the other coil is switched on, the water boils in 3 minutes If the two coils are connected in series the time taken to boil water in the kettle is:

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Explanation

$H_1 = { V^2 \over R_1 } t_1$ $ R_1 = { V^2 \over H_1} t_1 and R_2 = { V^2 \over H_2 } t_2$ $ { V^2 \over H_1 } = { V^2 \over H_2 } = const \therefore R\, \alpha \,t $ $ Now R_s = R_1 + R_2 $ t = 6 + 3 = 9 Minutes

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An electric kettle has two coils when one of these is switched on. the water in the kettle boils in 6 minutes. When the other coil is switched on, boils in 3 minutes If the two coils are connected in parallel, the time taken to boil water in the kettle is

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Explanation

$R_p = { R_1 R_2 \over R_1 + R_2 } $ $ t = {6 \times 3 \over 6 +3} = 2 minutes $

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The potential difference between the terminals of a battery is 10V and internal resistance $1 \Omega $ drops to 8V when connected across an external resistor find the resistance of the external resistor.

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Explanation

$ V = IR \,in I = { E \over R +r } $ $ \therefore ={ ER \over R + r } $

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A heater boils 1kg of water in time $t_1$ and another heater boils the same water in time $t_2$ If both are connected in series, the combination will boil the same water in time.

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At what temperature will the resistance of a copper wire be three times its value at 0°C ? (Given: temperature coefficient of resistance for copper = $4 \times 10^{-3} C^{-1}$ )

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Explanation

$R_\theta = R_\theta 0 [ 1 + \alpha ( \theta _2 - \theta _1 ) ] $ $ 3 = 1 + ( 4 \times 10 ^ {-3} ) T$ $ \therefore T = { 2 \over 4 \times 10 ^ {-3}} = 500 C $

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The resistance of a copper coil is $4.64 \Omega $ at 40 °C and $5.6 \Omega$ at 100 °C Its resistcnce at 0° C will be

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Explanation

$R_{40} [1 + \alpha (\theta_2 - \theta_1)]$ $ 5.6 = 4.64[1 + a(100 -40)] =4.64+278.4 a$ $a ={5.6 -4.64 \over 278.4} = 0.0035 C^{-1}$ $ \Rightarrow _{100} = R_0(1+ \alpha T_2) = R_0 [1+(0.0035 \times 100)]$ $ 5.6 = R_0 \times 1.35$ $Ro = 4 \Omega $

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There are n resistors having equal value of resistance r. First they are connected in such a way that the possible minimum value of resistance is obtained. Then they are connected in such a way that possible maximum value of resistance is obtained the ratio of minimum and maximum values of resistances obtained in these way is....

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Explanation

In parallal connection R minimum = r/n In Series connection R maximum= nr $ { R min \over R max } = { r \over n(n-1) } = {1 \over n^2}$

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Temperature of a conductor increases by $5 ^\circ $C passing electric current for some time. The increase in its temperature when double current is passed through the same conductor for the same time is $ ^ \circ C $

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Explanation

$ \triangle Q\, \alpha\, I^2 $ V is same so $ P_1 = { V^2 \over R_1 } and P_2 = {V^2 \over R_2} $

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Area of cross-section of two wires of same length carrying same current is in the ratio of 1 : 2. Then the ratio of heat generated per second in the wires = ....

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Explanation

$ I , \rho , l are equal so H \alpha {1 \over A} $ $ \therefore {H_1 \over H_2} = {A_2 \over A_1} = {2 \over 1} $

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If $ \sigma_1, \sigma_2, \sigma_3$ are the conductances of three conductor then equivalent conductance when they are joined in series, will be.

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Explanation

$ Reff = R_1 =R_2 +R_3 \Rightarrow {1 \over \sigma_eff} = { 1 \over \sigma _2 } + { 1 \over \sigma _3} $

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