de-Broglie wavelength of atom at T K absolute temperature will be....................
The de-Broglie wavelength of a particle is given by the formula: $$ ext{wavelength} = rac{h}{ ext{momentum}} $$ For an atom at temperature T, the momentum can be related to the thermal energy as $$ p = rac{mv}{ ext{thermal energy}} $$ The thermal energy is given by $$ rac{3kT}{2} $$ Therefore, the de-Broglie wavelength is $$ ext{wavelength} = rac{h}{ ext{momentum}} = rac{h}{ ext{mv}} rac{1}{ ext{thermal energy}} = rac{h}{ ext{mv}} rac{1}{ ext{(3kT/2)}} = rac{h}{ ext{mv}} rac{1}{ ext{(3kT/2)}} = rac{h}{ ext{sqrt}(3mkT)} $$