Physics MCQs for NEET — Practice Questions with Answers

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A resistor $ 30 \Omega $ , inductor of reactance $ 10 \Omega $ and the capacitor of reactance $ 10 \Omega $ are connected in series to an ac voltage source$ e = 300 \sqrt 2 sin (\omega t) $ The current in the circuit is

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Explanation

$ I_{rms } = { \upsilon _ {rms } \over |z| } =300 /30 = 10 A $

Same current is flowing in two alternating circuits.The first circuits contains only inductance andthe other contains only a capacitor. If the frequency of the emf of ac is increased the effect on the value of the current will be.

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Explanation

In an inductive circuit, the current \( I \) is inversely proportional to the frequency \( f \) of the AC supply, according to the formula \( I = \frac{V}{\omega L} \). Thus, as frequency increases, the current decreases. In a capacitive circuit, the current is directly proportional to the frequency, according to \( I = \omega CV \). Hence, as frequency increases, the current increases. Therefore, the effect of increasing frequency is a decrease in current for an inductive circuit and an increase in current for a capacitive circuit.

A 20 volts ac is applied to a circuit consisting of a resistance and a coil with negligible resistance. If the voltage across the resistance is 12 V, the voltage across the coil is,

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An alternating voltage $ E=200 \sqrt 2 sin (100t) $ is connected to 1 microfarad capacitor through an ac ammeter. The reading of the ammeter shall be.

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In a region of uniform magnetic induction $B = 10^{-2} tesla $, a circular coilof radius 30 cm and resistance $ \pi^ 2 ohm $ is rotated about an axis which is perpendicular to the direction of B and which forms a diameter of the coil. If the coil rotates at 200 rpm the amplitude of the alternating current induced in the coil is,

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Explanation

$ I_0 = { NAB \Omega \over R } $

An LCR series circuit with $ R = 100 \Omega $ is connected to a 200 V, 50 Hz a.c source when only the capacitance is removed the current lies the voltage by $ 60 ^ \circ $ when only the inductance is removed, the current leads the voltage by $ 60 ^\circ $ . The current in the circuit is

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Explanation

for inductor $ tan \theta = { \omega L \over R } $ for capacitor $ tan \theta = { 1 \over \omega CR } $ $ |\theta | is same 50 , \omega L = { 1 \over \omega C } $ means resonance $I _ {rms} = { \upsilon _{rms} \over R} $

The power factor of a good choke coil is

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Explanation

The power factor of a choke coil depends on the phase difference between the voltage and the current. For a good choke coil, which is highly inductive, the phase difference is close to 90 degrees. The power factor (

$$ cos \\phi $$

) is given by:

$$ cos \\phi = \\cos (90^\circ) $$

$$ cos \\phi = 0 $$

However, in practical scenarios, it is not exactly zero due to the presence of some resistance. Therefore, it is nearly zero. Thus, the power factor of a good choke coil is nearly zero.

When 100 volt dc is applied across a coil, a current of 1A flows through it. When 100 volt ac at $50 cycle s^{-1} $ is applied to the same coil, only 0.5 A current flows. The impedance of the coil is,

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Explanation

When 100V DC is applied, the resistance (R) of the coil can be found using Ohm's Law: $$ R = rac{V}{I} = rac{100V}{1A} = 100 ext{ ohms} $$ When 100V AC is applied, the current is 0.5A. The impedance (Z) can be found using the same formula: $$ Z = rac{V}{I} = rac{100V}{0.5A} = 200 ext{ ohms} $$ Therefore, the impedance of the coil is 200 ohms.

An LC circuit contains a 20 mH inductor and a $50 \mu F $ capacitor with an initial charge of 10 mc. The resistance of the circuit is negligible. At the instant the circuit is closed be t = 0. At what time is the energy stored compeletly magnetic.

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Explanation

$ t = { T \over 4 } = { 2 \pi \sqrt{LC } \over 4 } $

The quality factor of LCR circuit having resistance (R) and inductance (L) at resonance frequency $( \omega )$ is given by

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Explanation

The quality factor (Q) of an LCR circuit at resonance is given by the formula: $$ Q = \frac{\omega L}{R} $$ where \( \omega \) is the angular frequency, \( L \) is the inductance, and \( R \) is the resistance. This is because, at resonance, the impedance of the circuit is minimized, and the quality factor is defined as the ratio of the energy stored in the circuit to the energy dissipated per cycle.

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