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In an AC circuit containing only a capacitor, what is the phase relationship between the voltage across the capacitor and the current flowing through it?
The NCERT text states, 'The current through the capacitor is $\pi/2$ ahead of the applied voltage.'
In a series RLC AC circuit, if VR, VL, and VC represent the voltage phasors across the resistor, inductor, and capacitor, respectively, and I is the current phasor, which of the following is correct regarding their phase relationships?
According to the NCERT text, 'From previous section, we know that VR is parallel to I, VC is $\pi/2$ behind I and VL is $\pi/2$ ahead of I.'
The total voltage V across a series RLC circuit connected to an AC source is represented by the phasor addition of individual voltage phasors. If VL, VR, and VC are the voltage phasors across the inductor, resistor, and capacitor respectively, which equation correctly represents the total voltage phasor?
The NCERT text states, 'The phasor relation whose vertical component gives the above equation is $\text{VL} + \text{VR} + \text{VC} = \text{V}$'.
In a series RLC circuit, if the capacitive reactance (XC) is greater than the inductive reactance (XL), what can be concluded about the circuit and the phase of the current relative to the source voltage?
The NCERT text explains, 'If XC > XL, $\phi$ is positive and the circuit is predominantly capacitive. Consequently, the current in the circuit leads the source voltage.'
Consider an RLC series circuit. If the impedance triangle has resistance R as its base, and the hypotenuse is the impedance Z, then the vertical side of the triangle (opposite the phase angle $\phi$) represents:
From the impedance diagram (Fig. 7.12) and the formula for impedance $Z = \sqrt{R^2 + (X_C - X_L)^2}$, the vertical side of the right-triangle is $(X_C - X_L)$ or $(X_L - X_C)$ depending on which reactance is larger. The magnitude is $|X_C - X_L|$.
Which of the following is a disadvantage of using the phasor diagram method for analyzing AC circuits?
The NCERT text states, 'This method of analysing ac circuits suffers from certain disadvantages. First, the phasor diagram say nothing about the initial condition.'
The phase angle $\phi$ for a series RLC circuit, which determines the phase difference between the source voltage and the current, can be determined using the formula:
The NCERT text (Eq. 7.27) states, '$\tan\phi = \frac{X_C - X_L}{R}$'.
A phasor is defined as a vector that rotates about the origin. What does its angular speed represent?
The NCERT text defines a phasor as 'a vector which rotates about the origin with angular speed $\omega$'.
In a series RLC circuit, the current phasor I is commonly drawn horizontally as a reference. In this representation, where would the voltage phasor across the resistor (VR) be located?
The NCERT notes that in an RLC circuit, 'VR is parallel to I'. This means they are in phase and drawn in the same direction on a phasor diagram.
If the voltage across an AC source is given by $v = v_m \sin(\omega t)$ and the current in a particular circuit element is $i = i_m \sin(\omega t + \pi/2)$, which type of element is predominant in determining the phase relationship?
The current waveform $i = i_m \sin(\omega t + \pi/2)$ indicates that the current leads the voltage by $\pi/2$. This phase relationship is characteristic of a purely capacitive circuit, where the current through the capacitor is $\pi/2$ ahead of the applied voltage.
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.