Physics MCQs for NEET — Practice Questions with Answers

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The coefficient of linear expansion ($\alpha_l$) has units of:

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Explanation

The definition $\Delta l/l = \alpha_l \Delta T$ implies that $\alpha_l = (\Delta l/l) / \Delta T$. Since $\Delta l/l$ is dimensionless, the unit of $\alpha_l$ is the inverse of the unit of temperature change, which is $K^{-1}$ (or $^\circ C^{-1}$). The table also lists units as $10^{-5} K^{-1}$.

Which of the following materials typically has a higher value of coefficient of linear expansion?

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Explanation

The context states: 'Normally, metals expand more and have relatively high values of $\alpha_l$.' Table 10.1 confirms metals like Aluminium, Brass, Iron, Copper, Silver, Gold have higher values compared to Glass (pyrex) and Lead.

If a rectangular sheet of a solid material has a length 'a' and breadth 'b', and its temperature increases by $\Delta T$, the increase in length $\Delta a$ can be expressed as:

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Explanation

The example for area expansion shows that when the temperature increases by $\Delta T$, 'a' increases by $\Delta a = \alpha_l a \Delta T$ and 'b' increases by $\Delta b = \alpha_l b \Delta T$. This directly refers to linear expansion.

The phenomenon where a blacksmith heats an iron ring before fitting it on the rim of a wooden wheel of a horse cart is an application of:

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Explanation

The introduction section mentions: 'you will find out why blacksmiths heat the iron ring before fitting on the rim of a wooden wheel of a horse cart'. This is a classic application of thermal expansion, where the ring expands on heating, allowing it to fit, and then contracts on cooling, forming a tight fit.

Which of the following statements is TRUE regarding the equivalent internal resistance of cells connected in series?

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Explanation

According to the NCERT text, 'The equivalent internal resistance of a series combination of n cells is just the sum of their internal resistances.' (Eq. 3.46 for two cells extends to n cells).

Two cells with emfs $\epsilon_1$ and $\epsilon_2$ and internal resistances $r_1$ and $r_2$ respectively, are connected in series such that the negative terminal of the first cell is connected to the positive terminal of the second cell. What is the equivalent emf of this combination?

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Explanation

The NCERT text states, 'Consider first two cells in series (Fig. 3.13), where one terminal of the two cells is joined together leaving the other terminal in either cell free. ...eeq = $\epsilon_1$ + $\epsilon_2$' (Eq. 3.45). This refers to the arrangement where the negative of one is connected to the positive of the other, resulting in additive emfs.

If two cells with emfs $\epsilon_1$ and $\epsilon_2$ (${\epsilon_1} > {\epsilon_2}$) and internal resistances $r_1$ and $r_2$ are connected in series such that their negative terminals are joined together, what will be the equivalent emf?

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Explanation

The NCERT text mentions: 'If instead we connect the two negatives, Eq. (3.42) would change to $V_{BC} = -\epsilon_2 - Ir_2$ and we will get $e_{eq} = \epsilon_1 - \epsilon_2$ (${\epsilon_1} > {\epsilon_2}$)' (Eq. 3.47). This indicates that when cells are connected in opposition (e.g., negative to negative or positive to positive), their emfs subtract.

For n cells, each with emf $\epsilon$ and internal resistance $r$, connected in series, the equivalent internal resistance ($r_{eq}$) is given by:

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Explanation

The NCERT text states, 'The equivalent internal resistance of a series combination of n cells is just the sum of their internal resistances.' For n identical cells, $r_{eq} = r + r + ... + r$ (n times) $= n r$.

Consider two cells in parallel. If their positive terminals are connected together and their negative terminals are connected together, and $I_1$ and $I_2$ are the currents leaving the positive electrodes, which statement is true about the total current I flowing out of the combination?

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Explanation

For cells in parallel (Figure 3.14), the NCERT text states, 'At the point B1, I1 and I2 flow in whereas the current I flows out. Since as much charge flows in as out, we have $I = I_1 + I_2$' (Eq. 3.48). This follows Kirchhoff's current rule (junction rule).

For a parallel combination of 'n' cells with emfs $\epsilon_1, ..., \epsilon_n$ and internal resistances $r_1, ..., r_n$ respectively, the equivalent internal resistance $r_{eq}$ is given by:

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Explanation

According to the NCERT text, for a parallel combination of n cells, the equivalent internal resistance is given by ' $1/r_{eq} = 1/r_1 + ... + 1/r_n$' (Eq. 3.58).

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