NEET प्रश्न (MCQ) हिंदी में — उत्तर और विस्तृत हल सहित

$at \,t = 0 \; \;\; N =No$ $ t = T_ {1/2} \times 1 \;\;\; N = No/2 \;\;\; \therefore {N \over No} = {1 \over 16}$ $ t = T_ {1/2} \times 2 ;;; N = No/4 ;;; {N\over No} \times 100 = { 1 \over 32 } \times 100$ $ t = T_ {1/2} \times 3 \;\;\; N = No/8 \;\;\; =3.125 $ $ t = T_ {1/2} \times 4 \;\;\; N = No/16 \;\;\; \approx 3 \%$ $ t = T_ {1/2} \times 5 \;\;\; N = No/32 $

$ _ZX^A \rightarrow _{Z+1}Y^A \rightarrow _{Z-1}B^{A-4} \rightarrow _{Z-1}B^{A-4}$

माध्य जीवन (T) में विश्राम द्रव्यमान = $No/ e$ $ T = { 1 \over \lambda } \Rightarrow \lambda = {1 \over 5 } min ^{-1}$ $ N = N0e^{- \lambda t}$ $ N0/2 = N0e^{-1/5 t}$ $m2 = { 1\over 5}t $ $ {1 \over 2 } = e^{-1/5} t $ $ t = 5ln2$ $ 2^{-1} = e^{-1/5} t $ $ t = 5 log e^2$ $ 2^1 = e {1 \over 5 } t $

${dN \over df} = df \Rightarrow I = dN$ $ I^1 = \lambda N_1 $ $ I_2 = \lambda N_2 $ $ {I_1 \over N_1} = \lambda $ $ {I_1 \over N_2} = \lambda $ $\therefore {I_1 \over N_1} = { f_2 \over N_2} \Rightarrow I_2 = { I_2 \over N_1} \times N_2 = { 3 \times 10^{10} \times 2 \times 10^{15} \over 2 \times 10_20} = 3 \times 10^5 $

Thomson मॉडल

$\triangle E= E_4 - E_1 = {-13.6 \over 4} - ({-13.6 \over 1})= 0.85 +13.6 = 12.75 ev$