NEET Practice Questions (MCQs) with Answers & Solutions

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The mass of an α-particle is 

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Explanation

(a) This is due to mass defect because a part of mass is used in keeping the neutrons and protons bound as α-particle.

Atomic number of a nucleus is Z and atomic mass is M. The number of neutron is

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Explanation

(a) N = M-Z = Total no. of nucleons – no. of protons.

The α-particle is the nucleus of an atom of

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Explanation

(c) α-particle is Helium-nucleus.

The force acting between proton and proton inside the nucleus is 

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Explanation

(c) Both coulomb and nuclear force act inside the nucleus.

For a nucleus to be stable, the correct relation between neutron number N and Proton number Z is

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Explanation

(d) For stability in case of lighter nuclei NZ=1 and for heavier nuclei NZ>1.

Mn and MP represent mass of neutron and proton respectively. If an element having atomic mass M has N-neutron and Z-proton, then the correct relation will be

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Explanation

(a) Actual mass of the nucleus is always less than total mass of nucleons so M<NMn+ZmP

The radius of a nucleus of a mass number A is directly proportional to

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Explanation

(d) R=R0A1/3RA1/3

As compared C12 atom, C14 atom has

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Explanation

(c)  For C126 , p = 6, e = 6, n = 6

For C146, p = 6, e = 6, n = 8

If m, mn and mp are the masses of XAZ nucleus, neutron and proton respectively 

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Explanation

(a) The mass of nucleus formed is always less than the sum of the masses of the constituent protons and neutrons i.e. m<A-Zmn+Zmp.

On the bombardment of neutron with Boron. α-particle is emitted and product nuclei formed is

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Explanation

(c) B105+n10Li73+He42

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