NEET Practice Questions (MCQs) with Answers & Solutions

Practice free NEET NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Language English हिंदी
Register free for difficulty & keyword filters
● ● ● ● ●

Neutrino is a particle, which is 

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(c) Neutrino is a charge less, spin particle.

● ● ● ● ●

To generate a power of 3.2 mega watt, the number of fissions of U235 per minute is
(Energy released per fission = 200MeV, 1eV=1.6×10-19 J 

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) Number of fissions per second = Power outputEnergy released per fission=3.2×106200×106×1.6×10-19=1×1017

⇒ Number of fission per minute = 60×1017=6×1018

● ● ● ● ●

The average number of prompt neutrons produced per fission of U235 is 

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(c)

● ● ● ● ●

In the nuclear reaction: Xn, α 3Li7 the term X will be 3

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) Xn, α 3Li7⇒XZA+n01→Li37+He24

Z = 3+2 = 5 and A = 7+4-1 = 10

∴X510=B510

 

● ● ● ● ●

In an atomic bomb, the energy is released due to

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) The energy is released due to bombarding of neutrons on U23592

● ● ● ● ●

If an electron and a positron annihiliate, then the energy released is 

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(b) Mass of electron = mass of positron = 9.1×10-31kg
Energy released E=(2m)c2
= 2×9.1×10-31×(3×108)2=1.6×10-13 J

● ● ● ● ●

The energy liberated on complete fission of 1 kg of U92235 is (Assume 200 MeV energy is liberated on fission of 1 nucleus) 

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(c) Mass of a uranium nucleus =92×1.6725×10-27+143×1.6747×10-27=393.35×10-27 kg

Number of nuclei in the given mass =1393.35×10-27=2.542×1024

Energy released =200×2.542×1024 MeV

=5.08×1026 MeV=8.135×1013J=8.2×1013J

● ● ● ● ●

The nuclear reaction H12+H12→He24 (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(a) Total mass of reactants =2.0141×2=4.0282 amu
Total mass of products =4.0024 amu
Mass defect = 4.0282 amu-4.0024 amu = 0.0258 amu

∴ Energy released E = 931×0.0258 = 24 MeV

● ● ● ● ●

In the following reaction the value of ‘X’ is  
N714+He24→X+H11

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(b) N714+He24→O817+H11

● ● ● ● ●

Which of the following are suitable for the fusion process

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

(b) Fusion process results in increase in mass number. For light nuclei, fusion process increases the binding energy per nucleon which increases stability. So light nuclei are suitable for fusion process.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every NEET question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.