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The radioactive decay of uranium into thorium is expressed by the equation U92238Th90234+X where 'X' is

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Explanation

(d) U92238Th90234+He24

In a radioactive decay, neither the atomic number nor the mass number changes. Which of the following would be emitted in the decay process 

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Explanation

(d) In photon decay the mass no. and atomic mass remain the same.

The half life (T) and the disintegration constant λ of a radioactive substance are related as

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Explanation

(b) By using N=N0e-λtN02=N0e-λT1/22=eλT1/2
By taking loge both the side
loge2=λT1/2λT1/2=0.693

The half life period of a radioactive substance is 5 min. The amount of substance decayed in 20 min will be

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Explanation

(a) Number of half lives in 20 min = n = 205=4 
Fraction of material remains after four half lives =116
Hence fraction that decays 1-116=1516=93.75%

In the uranium radioactive series, the initial nucleus is U92238 and the final nucleus is Pb82206. When the uranium nucleus decays to lead, the number of  α-particles emitted will be 

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Explanation

(d) nα=A-A'4=238-2064=8

Which of the following is a correct statement

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Explanation

(a) Both the β-rays and the cathode rays are made up of electrons. γ-rays are EM waves, α-particles are doubly ionized helium atoms and protons and neutrons have approximately the same mass.

Ne22 nucleus after absorbing energy decays into two α-particles and an unknown nucleus. The unknown nucleus is 

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Explanation

(b) N1022He24+He24+X614 ;  hence X is carbon

The half life of I131 is 8 days. Given a sample of I131 at time t = 0, we can assert that 

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Explanation

(d) Number of nuclei decreases exponentially
N=N0e-λt  and Rate of decay -dNdt=λN
Therefore, decay process losts up to t = .
Therefore, a given nucleus may decay at any time after t = 0.

Carbon-14 decays with half-life of about 5,800 years. In a sample of bone, the ratio of carbon-14 to carbon-12 is found to be 14 of what it is in free air. This bone may belong to a period about x centuries ago, where x is nearest to 

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Explanation

 (a) To becomes 14th, it requires time of two half lives
i.e., t = 2(T1/2) = 2×5800 = 2×58 centuries

In the disintegration series U92238αXβ-YZA
the values of Z and A respectively will be 

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Explanation

(d) U92238αXβ-Y91234

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