NEET Practice Questions (MCQs) with Answers & Solutions

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The mass of one molecule of compound C60 H122 is:

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Explanation

Mass of one molecule of C60 H122=12×60+122 amu                                                            = 842 amu                                                            = 842×1.66×10-24 g                                                            = 1.4×10-21 g

Read the following statements (S) and Explanation (E). Choose the correct answers from the codes

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Explanation

Explanation is correct reason for statement.

Read the following statements (S) and Explanation (E). Choose the correct answers from the codes

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Explanation

ans 3,

 

Certain elements combine with other atoms, donating, accepting or sharing electrons in different proportions depending on the nature of the reaction. 

Which of the following sets of quantum numbers represent an impossible arrangement - 

       n   l    m     s

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Explanation

(C) If l=2, m  -3

How many unpaired electrons are present in Ni2+ cation (atomic number = 28)

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Explanation

The electron configuration of Ni (atomic number 28) is 1s^2 2s^2 2p^6 3s^2 3p^6 3d^8 4s^2. When forming the Ni^2+ cation, the two 4s electrons are removed, leaving a configuration of 3d^8. The 3d subshell can hold 10 electrons, so there are 2 unpaired electrons in Ni^2+.

Number of unparired electrons in 1S2 2S2 2P3 is -

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Explanation

The given electronic configuration 1s^2 2s^2 2p^3 has 3 unpaired electrons, one each in the 2p orbitals. This is because the 2p subshell can hold a maximum of 6 electrons, and with 3 electrons present, there are 3 unpaired electrons.

The quantum numbers of four electrons are given below.

                                  n            l           m          s 

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Explanation

(C)

The correct order of decreasing energy will be electron 3 which has higher energy than 2 and in the order given.

E1 =  3s

E2 =  4s

E3 =  3d

E4=  3p

Which type of radiation is not emitted by the electronic structure of atoms:

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Explanation

(D) y-rays emission occurs due to radioactive change, a nuclear phenomenon.

In Rutherford's alpha scattering experiment using gold foil, the kinetic energy of the alpha particle was 1.2 x 10-12J. For a head on collision, using the formula K.E. = 14πε0x 2Ze2/r0 , what may be the magnitude of r0 [ The nuclear radius of gold, Z=79; 14πε0= 9 x 109 new-ton/meter2 coulomb-2, e= 1.6x10-19 coulomb]

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Explanation

1.2 x 10-12= 9 x 109 x 2x79x[1.6x10-19]2 / r0

r0 = 9 x 79 x 256 x 2 x10-38 x 109 / 1.2 x 10-12 = 3 x 10-14m

The frequency of line spectrum of sodium is 5.09 x 1014 sec-1. Its wavelength (in nm) will be -[C= 3x108m/sec]

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Explanation

(C) λ=3×108m.sec-15.09×1014m.sec-1

=0.5892 x 10-6 = 589.4 x 10-9m = 589nm

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