NEET Practice Questions (MCQs) with Answers & Solutions

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In the long form of periodic table, the elements having lowest ionization potential are placed in:

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Explanation

(a) Ionization potential increases along period.

Which one of the elements with the following outer orbital configurations may exhibit the largest number of oxidation states?

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Explanation

(c)

For transition metal elements a general rule is = The max number of oxidation states = no. unpaired d-orbital electrons + the 2s electrons.

 

In 3d5 4s2 configuration

Number of unpaired d-electrons = 5

Hence Maximum number of oxidation states = 5+2=7

Such as Mn+7

The law of triads applicable to a group of:

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Explanation

(a) The average atomic mass of,

Br=At. wt. of Cl+At. wt. of I2

In the long form of periodic table all the non-metals are placed under:

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Explanation

s,d ,f block have metal only , where as p block has metal, nonmetal and metalloid .

General electronic configuration of the transition elements is given by:

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Explanation

(d) It is a fact.

 

The statements that is not correct for the periodic classification of elements is:

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Explanation

(d) In Cr 3d5, 4s1 and in Cu 3d10 4s1  

Which of the following is not a metal?

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Explanation

(d) It belongs to VI A gp. and all the elements are non-metals, except Po of this gp.

The ions O2-, F-, Na+, Mg2+ and Al3+ are isoelectronic. Their ionic radii show [2003]

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Explanation

The ionic radii of isoelectronic ions (ions with the same number of electrons) show a significant decrease from O2- to Al3+. This is because as the nuclear charge increases from O2- to Al3+, the electrons are more tightly bound to the nucleus, resulting in a smaller ionic radius.

The example of metalloid elements in the periodic table is:

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Explanation

(c) B and Si both have intermediate properties between metals and non-metals.

The element with atomic number 26 is:

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Explanation

(c) Iron (Fe) has atomic number 26.

 

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