In the long form of periodic table, the elements having lowest ionization potential are placed in:
(a) Ionization potential increases along period.
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In the long form of periodic table, the elements having lowest ionization potential are placed in:
(a) Ionization potential increases along period.
Which one of the elements with the following outer orbital configurations may exhibit the largest number of oxidation states?
(c)
For transition metal elements a general rule is = The max number of oxidation states = no. unpaired d-orbital electrons + the 2s electrons.
In 3d5 4s2 configuration
Number of unpaired d-electrons = 5
Hence Maximum number of oxidation states = 5+2=7
Such as Mn+7
The law of triads applicable to a group of:
(a) The average atomic mass of,
Br=
In the long form of periodic table all the non-metals are placed under:
s,d ,f block have metal only , where as p block has metal, nonmetal and metalloid .
General electronic configuration of the transition elements is given by:
(d) It is a fact.
The statements that is not correct for the periodic classification of elements is:
(d) In Cr 3d5, 4s1 and in Cu 3d10 4s1
Which of the following is not a metal?
(d) It belongs to VI A gp. and all the elements are non-metals, except Po of this gp.
The ions O2-, F-, Na+, Mg2+ and Al3+ are isoelectronic. Their ionic radii show [2003]
The ionic radii of isoelectronic ions (ions with the same number of electrons) show a significant decrease from O2- to Al3+. This is because as the nuclear charge increases from O2- to Al3+, the electrons are more tightly bound to the nucleus, resulting in a smaller ionic radius.
The example of metalloid elements in the periodic table is:
(c) B and Si both have intermediate properties between metals and non-metals.
The element with atomic number 26 is:
(c) Iron (Fe) has atomic number 26.
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