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NEET NEET Questions — Free MCQ Practice

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Which of the following statements is not correct?

A.

The first ionization energies (in KJ $m o l^{- 1}$ ) of carbon, silicon, germanium, tin, and lead are 1086, 786, 761, 708 and 715 respectively.

B.

Down the group, electronegativity decreases from B to Tl in boron family.

C.

Among oxides of the elements of carbon family, CO is neutral, GeO is acidic and SnO is amphoteric.

D.

The 4f- and 5f- inner transition elements are placed separately at the bottom of the periodic table to maintain its structure.

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Explanation

(A), (C) and (D) are correct statements

(B) First decreases from B to Al and then increases marginally owing to discrepancies in atomic size of the element.

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Which of the following orders is correct?

A.

F>N>C>Si>Ga -non-metallic character.

B.

F>Cl>O>N - oxidising property.

C.

C<Si>P>N - electron affinity value.

D.

All of these.

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Explanation

(D) (A) As electronegativity increases the non-metallic character increases as tendency to form anion increases.

(B) It is based on their SRP values. (Oxidising power may be cumulative effect of hydration energies, electronegativities, bond dissociation energies and electron gain enthalpies)

(C) C =-121; Si = -135; P =-60; N = +31 (all values are in KJ/mole). It depends on various factors like size of atom, nuclear charge, partially filled, half filled and completely filled electronic configurations.

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If the same element is forming oxides in different oxidation states then :

A.

that oxides will be neutral in nature in which element will be in its highest oxidation state.

B.

that oxide will be highest acidic in nature in which element will be in this highest oxidation state.

C.

that oxide will be amphoteric in nature in which element will be in its highest oxidation state.

D.

that oxide will be highly basic in nature in which element will be in its highest oxidation state.

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Explanation

(B) Oxidation state $\propto$ electronegativity.

Electronegativity increases with increase in oxidation state; so the difference in electronegativity decreases (between element and oxygen) and acidic character increases.

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Assertion : The $5^{t h}$ period of periodic table contains 18 elements and not 32.

Reason : n = 5, –1 = 0, 1, 2, 3. The order in which the energy of available orbits 4d, 5s and 5p increases is 5s < 4d < 5p and the total number of orbitals available are 9 and thus 18 electrons can be accommodated.

A. If both the assertion and the reason are true and the reason is a correct explanation of the assertion B. If both the assertion and reason are true but the reason is not a correct explanation of the assertion C. If the assertion is true but the reason is false D. If both the assertion and reason are false

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Explanation

The order in which the energy of available orbitals `4d,5s` and 5p increases is `5s lt 4d lt 5p` and the total number of orbitals avaiable are 9 and thus 18 electrons can be accommodated

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Assertion : :The 4f- and 5f- inner transition series of elements are placed separately at
the bottom of the periodic table.

Reason : (i) This prevents the undue expansion of the periodic table i.e., maintains its structure.
(ii) This preserve the principle of classification by keeping elements with similar properties in a single column.

A. If both the assertion and the reason are true and the reason is a correct explanation of the assertion B. If both the assertion and reason are true but the reason is not a correct explanation of the assertion C. If the assertion is true but the reason is false D. If both the assertion and reason are false

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Explanation

(A)

4f and 5f - inner transition series of elements are placed separately at the bottom of the periodic table. It is because

1) It prevents the undue expansion of the periodic table i.e. maintains it's structure.

2) This preserves the principle of classification by keeping elements with similar properties in a single column.

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Assertion : Manganese (atomic number 25 ) has a less favourable electron affinity than its neighbours on either side because.

Reason : The Manganese has stable, ${[A r]}^{18} 3 d^{5} 4 s^{2}$ electrons configuration.

A. If both the assertion and the reason are true and the reason is a correct explanation of the assertion B. If both the assertion and reason are true but the reason is not a correct explanation of the assertion C. If the assertion is true but the reason is false D. If both the assertion and reason are false

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Explanation

(A) The magnitude of and element’s electron affinity depends on the element’s valence shell electrons
configuration.

${}_{25}M n = {[A r]}^{18} 3 d^{5} 4 s^{2}$ configuration,

${}_{25}C r = {[A r]}^{18} 3 d^{5} 4 s^{1}$ configuration

${}_{25}F e = {[A r]}^{18} 3 d^{6} 4 s^{2}$ configuration

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Assertion : Fluorine forms only one oxoacid, HOF because,

Reason : Fluorine has small size and high electronegativity.

A. If both the assertion and the reason are true and the reason is a correct explanation of the assertion B. If both the assertion and reason are true but the reason is not a correct explanation of the assertion C. If the assertion is true but the reason is false D. If both the assertion and reason are false

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Explanation

(A) High electronegativity and small size, has only – oxidation state.

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The correct calculate value for $△ H$ for

$M (s) \to M^{2 +} (a g)$

From following arbitrary value

$M (s) \to M (g); △ H = 1000 K J m o l^{- 1} M (g) \to M^{+} (g); △ H = 750 K J m o l^{- 1} M^{+} (g) \to M^{2 +} (g); △ H = 1200 K J m o l^{- 1} M^{2 +} (g) + a q \to M^{2 +} (a q .); △ H = - 1800 K J m o l^{- 1}$

A.

1950 KJ mol^-1

B.

1150 KJ mol^-1

C.

2300 KJ mol^-1

D.

None of these

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Explanation

$△ H = △ H_{s u b} + I E_{1} + I E_{2} + △ H_{h y d r a t i o n} = 1000 + 750 + 12000 + (- 1800) △ H = 1150 K J m o l^{- 1}$

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Read the following statements (S) and Explanation (E). Choose the correct answers from the codes

A.

,

B.

,

C.

and

D.

:

S : Sulphate is estimated as ${BaSO}_{4}$ and not as ${MgSO}_{4}$ .

E : Ionic radius of ${Mg}^{2 +}$ is smaller than ${Ba}^{2 +}$ .

1. S is correct but E is wrong
2. S is wrong but E is correct
3. Both S and E are correct and E is correct explanation of S
4. Both S and E are correct but E is not correct explanation of S

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Explanation

${BaSO}_{4}$ is insoluble.

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Which of the following would have a permanent dipole moment ?

A.

BF₃

B.

SiF₄

C.

SF₄

D.

XeF₄

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