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NEET NEET Questions — Free MCQ Practice

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The molecule having a high dipole moment among the following is-

A.

H₂S

B.

BF₃

C.

CO₂

D.

CCl₄

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Explanation

It is an unsymmetrical molecule with the bond angle H-S-H slightly greater than $90^{\circ}$ .

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Allyl cyanide; C₃H₅CN has-

A.

9 sigma bonds and 4 pi bonds

B.

9 sigma bonds, 3 pi bonds and 1 lone pairs

C.

8 sigma bonds and 5 pi bonds

D.

8 sigma bonds, 3 pi bonds and 4 non-bonding electrons.

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The hybridization of carbon atoms in C-C single bond of $C \equiv C - C H = C H_{2}$ is-

A.

$s p^{3} - s p^{3}$

B.

$s p^{2} - s p$

C.

$s p - s p$

D.

$s p^{3} - s p$

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Explanation

As the first carbon has triple bond and second one has double bond with other two carbon atom.

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C-C bond in C₂H₆ undergoes heterolytic fission, the hybridisation of carbon is/are-

A.

$s p^{2}$

B.

$s p^{3}$

C.

$s p^{2}, s p^{3}$

D.

$s p, s p^{2}$

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Explanation

During heterolytic fission there will be formation of CH₃⁺ and CH₃^- which has sp² and sp³ hybridization respectively.

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The enolic form of acetone contains how many $σ$ bonds (a), $π$ bonds (b) and lone pairs (c)-

A.

9a, 1b, 2c

B.

8a, 2b, 2c

C.

10a, 1b, 1c

D.

9a, 2b, 1c

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The mean free path ( $λ$ ) of a gas sample is given by:

A.

$λ = \sqrt{2} π σ^{2} N$

B.

$λ = 1 / \sqrt{2} π σ^{2} N$

C.

$λ = \sqrt{2} π μ σ^{2} N$

D.

none of these

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Explanation

(b) A derivation for mean free path of gas.

If v is the velocity of the moving molecule then in one second it will collide with all moleculeswith in a distance σ between the centres.
In one second it sweeps a volume πσ²v where any other molecule will collide with it.
If n is the total number of molecules per unit volume, then nπσ²v is number of collisions a molecule suffers in one second.
If v is the distance traversed by molecule in one second then mean free path is given by
     λ = total distance traversed in one second /no. of collision suffered by the molecules
      =v/πσ²vn
      =1/πσ²n
This expression was derived with the assumption that all the molecules are at rest except the one which is colliding with the others.

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Which is lighter than dry air?

A.

Moist air

B.

SO₂

C.

Cl₂

D.

O₂

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Explanation

(a) Molar mass of moist air is lesser than dry air.

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The ratio a/b (the terms used in van der Waals' equation) has the unit:

A.

atm lire mol^-1

B.

atm dm³ mol^-1

C.

dyne cm mol^-1

D.

all of these

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Explanation

(d) The units of 'a; are: atm litre² mol^-2

= atm dm⁶mol^-2 = dyne cm²mol^-2

The units of 'b' are: litre mol^-1 = dm³mol^-1 = cm³mol^-1

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In the vander Waals' equation, the constant 'a' and 'b' with temperature shows which trend:

A.

both remains same

B.

'a' remains same, 'b' varies

C.

'a' varies, 'b' remains same

D.

both varies

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Explanation

(d) This is one of the limitation of vander Waal's equation.

'a' is measure of force, which is sensitive for distance, with increase in temp, the distance between molecule increase,so magnitude of force decrease. 'b' is measure of size, which is not so sensitive as 'a' . but it also changes.

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At relatively high pressure, van der Waals' equation reduces to:

A.

PV = RT

B.

PV = RT + a/v

C.

PV = RT + Pb

D.

PV = RT - a/V²

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Explanation

(c) At high pressure, volume of molecules should not be neglected in comparison to volume of gas. Also experimental to volume of gas. Also, experimental studies reveals PV > RT at high P.

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