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One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K)(4.0 atm, 5.0 L, 245 K) with a change in internal energy, U = 30.0 L atm. The change in enthalpy (H) of the process in L atm is:

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Explanation

(c) H=U + PV

      ... H2-H1 = U2-U1+(P2V2 - P1V1)

      ...     H = 30 + (4x5 - 2x3) = 44 L atm

At absolute zero, the entropy of a perfect crystal is zero. This is........... of thermodynamics.

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Explanation

(c) This is definition of third law of thermodynamics.

At constant pressure and temperature, the direction of any chemical reaction is one where, the...... decrease.

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Explanation

(c) Spontaneous process shows a decrease in G

The work done by a mass less piston in causing an expansion V (at constant temperature), when the opposing pressure, P is variable, is given by:

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Explanation

(a) Wrev-PdV or -PV; note that opposing pressure is not constant throughout.

Entropy decreases during:

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Explanation

(a) During solidification disorder decreases.

What is the entropy change for the reaction given below, 

2H2 (g) + O2 (g) 2H2O(l)

at temperature 300 K? Standard entropies of H2 (g), O2(g) and H2O(l) are 126.6, 201.20 and 68.0 JK-1mol-1 respectively.

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Explanation

(a) Sreaction = ΣSproduct-ΣSreactant               = 2 x SH2O-[2xSH2+SO2]

                  = 2 x 68-[2 x 126.6 + 201.20]

                  = -318.4 JK-1mol-1

If S° for H2, Cl2 and HCl are 0.13, 0.22 and 0.19 kJ K-1mol-1 respectively. The total change in standard entropy for the reaction, H2 + Cl2 2HCl is:

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Explanation

(a) S=SP-SR

          =(2 x0.19) - 0.13-0.22

          = 0.03 kJ K-1mol-1

          = 30 JK-1mol-1

In a flask, colourless N2O4(g) is in equilibrium with brown coloured NO2(g). At equilibrium when the flask is heated to 100°C, the brown colour deepens and on cooling it becomes coloured. Which statement is incorrect about this observation?

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Explanation

(c) H-U = nRT = 1 x 2 x 373 = 746 cal.

Enthalpy of the reaction,

 CH4(g) + 1/2 O2(g) CH3OH (l), is negative. If enthalpy of combustion of CH4 and CH3OH are x and y respectively, then which relation is correct?                                 

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Explanation

(b) CH4(g) + 1/2 O2(g) CH3OH (l)

      ..H=[(Hcof CH3OH)-(Hc of CH4)]

                = -[(-y)-(-x)]

                =-[y+x] =y-x

       ... x<y

Alternate explanation: 

CH4+2O2CO2+2H2O            H=xCH3OH+32O2CO2+2H2O    H=y

- (2)

CH4+12O2CH3OH x-y

As x - y < 0

x < y

In the reaction, H and S both are positive. In which of the following cases, the reaction would not be spontaneous?

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Explanation

(d) G=+ ve in a, and ZERO in b,c

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