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Work done during isothermal expansion of one mole of an ideal gas from 10 atm to 1 atm at 300 K is (Gas constant = 2) [AIIMS 2000]

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Explanation

W=+2.303nRT log p1p2

W=2.303×1×2×300 log 101=1381.8cal. 

Joule-Thomson expansion is [JIPMER 2000]

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Explanation

Joule-Thomson expansion is isoenthalpic.

thermodynamics, the Joule–Thomson effect (also known as the Joule–Kelvin effectKelvin–Joule effect) describes the temperature change of a real gas or liquid (as differentiated from an ideal gas) when it is forced through a valve or porous plug while keeping it insulated so that no heat is exchanged with the environment.[1][2][3]This procedure is called a throttling process or Joule–Thomson process.[4] At room temperature, all gases except hydrogenhelium and neon cool upon expansion by the Joule–Thomson process when being throttled through an orifice; these three gases experience the same effect but only at lower temperatures.[5][6] Most liquids such as hydraulic oils will be warmed by the Joule-Thomson throttling process.

The gas-cooling throttling process is commonly exploited in refrigeration processes such as air conditioners, heat pumps, and liquefiers.[7][8] In hydraulics, the warming effect from Joule-Thomson throttling can be used to find internally leaking valves as these will produce heat which can be detected by thermocouple or thermal-imaging camera. Throttling is a fundamentally irreversible process. The throttling due to the flow resistance in supply lines, heat exchangers, regenerators, and other components of (thermal) machines is a source of losses that limits the performance.

In an adiabatic expansion of an ideal gas [KCET (Med.) 2001; MH CET 2000]

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Explanation

q = ΔE – W, if q = 0 for adiabatic process, than ΔE = W.

For the reaction CH3COOH(l)+2O2(g)2CO2(g)+2H2O(l) at 25°C and 1 atm. pressure, ΔH = –874 kJ. Then the change in internal energy (ΔE) is …. [Orissa JEE 2002]

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Explanation

For this reaction Δn = 0 than ΔE = ΔH.

One mole of an ideal gas is allowed to expand freely and adiabatically into vacuum until its volume has doubled. A statement which is not true concerning this expression is [Pb. PMT 1998]

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Explanation

ΔS = 0 is not true.

At 27°C, one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm to 10 atm. The values of ΔE and q are (R = 2) [BHU 2001]

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Explanation

W=2.303nRTlogP2P1 

=2.303×1×2×300log102=965.84 

at constant temperature, ΔE = 0.

ΔE = q + w; q = –w = –965.84 cal.

ΔE° of combustion of isobutylene is –X kJ mol–1. The value of ΔH° is [DCE 2004]

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Explanation

(CH3)2C=CH2(g)+6O2(g)4CO2(g)+4H2O(l)

Δng=46=2 (i.e., negative)

we know that ΔH=ΔE+ΔngRT

=ΔE(Δng)RT (∵ Δng = –ve)

∴ ΔH < ΔE

An ideal gas expands in volume from 1 × 10–3 m3 to 1 × 10–2 m3 at 300 K against a constant pressure of 1 × 105 Nm–2. The work done is [AIEEE 2004]

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Explanation

W=PΔV=1×105(1×1021×103) 

=1×105×9×103=900 J  

The spontaneous flow of heat is always

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Explanation

Heat is always flow from the higher to lower temperature.

Mixing of non-reacting gases is generally accompanied by

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Explanation

Mixing of non-reacting gases increases randomness and so increase entropy.

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