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NEET NEET Questions — Free MCQ Practice

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KO₂ is used in oxygen cylinder in space air craft and submarines because it:

A.

absorbs CO₂ and increase O₂ content

B.

eliminate moisture

C.

absorbs CO₂

D.

produces O₂

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Explanation

(a) $2 {KO}_{2} + {CO}_{2} \overset{}{\to} K_{2} {CO}_{3} + \frac{3}{2} O_{2}$

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Tin dissolves in boiling caustic soda solution because of the formation of soluble:

A.

Sn(OH)₂

B.

Sn(OH)₄

C.

Na₂SnO₃

D.

none of these

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Explanation

(c) $Sn + 2 NaOH + H_{2} O \overset{}{\to} {Na}_{2} {SnO}_{3} + 2 H_{2}$

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Potash alum is used in purification of water because:

A.

it kills the micro-organisms

B.

it precipitates the colloidal matter

C.

it removes the hardness of water

D.

it catalyses the removal of impurities

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Explanation

(b) Al³⁺ is very good coagulant for negatively charged dispersion in water

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The pair of compounds which cannot exist together in solution is:

A.

NaHCO₃ and NaOH

B.

Na₂CO₃ and NaHCO₃

C.

Na₂CO₃ and NaOH

D.

NaHCO₃ and NaCl

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Explanation

(a) ${NaHCO}_{3} + NaOH \overset{}{\to} {Na}_{2} {CO}_{3} + H_{2} O Acid salt Alkali$

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Sodium burns in dry air to give:

A.

Na₂O

B.

Na₂O₂

C.

NaO

D.

Na₃N

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Explanation

(b) Li forms Li₂O, Na forms Na₂O₂ and rest all alkali metals forms superoxides MO₂.

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Which one is the highest melting point halide?

A.

NaCl

B.

NaBr

C.

NaF

D.

NaI

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Explanation

(c) NaF possesses most ionic character.

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The byproduct of Solvay process is:

A.

CO₂

B.

NH₃

C.

CaCl₂

D.

CaCO₃

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Explanation

(b)

An intermediate reaction in Solvay process gives CaCl₂;

$Ca (OH)_{2} + 2 {NH}_{4} Cl \overset{}{\to} {CaCl}_{2} + 2 {NH}_{3} + 2 H_{2} O$

In Solvay process, also known as ammonia soda process, carbon dioxide is passed through a brine solution (containing about 28 % NaCl) which is saturated with ammonia to form sodium carbonate.
$2 N H_{3} + H_{2} O + C O_{2} \to (N H_{4})_{2} C O_{3}$
$(N H_{4})_{2} C O_{3} + H_{2} O + C O_{2} \to 2 N H_{4} H C O_{3}$
$N H_{4} H C O_{3} + N a C l \to N a H C O_{3} ↓ + N H_{4} C l$

The precipitate of sodium bicarbonate is filtered, dried and ignited to form sodium carbonate.
$2 N a H C O_{3} h e a t N a_{2} C O_{3} + C O_{2} + H_{2} O$

The carbon dioxide required for the reaction can be obtained by heating limestone (calcium carbonate) to 1300 K in a lime klin. Lime dissolves in water to form calcium hydroxide which is then transferred to the ammonia recovery tower.
$C a C O_{3} h e a t C a O + C O_{2}$
$C a O + H_{2} O \to C a (O H)_{2}$

Ammonia required for the process can be prepared by heating ammonium chloride with calcium hydroxide.
$2 N H_{4} C l + C a (O H)_{2} 2 N H_{3} + C a C l_{2} + H_{2} O$

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The raw materials in Solvay process are:

A.

NaOH, CaO and NH₃

B.

Na₂CO₃, CaCO₃, and NH₃

C.

Na₂SO₄, CaCO₃ and NH₃

D.

NaCl, NH₃, CaCO₃

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Explanation

(d) Solvay process is based on electrolysis of brine (NaCl) solution.

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LiAlH₄ is obtained by reacting an excess of ...... with an etheral solution of AlCl₃.

A.

LiCl

B.

LiH

C.

Li

D.

LiOH

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Explanation

(b) $4 LiH + {AlCl}_{3} \overset{}{\to} {LiAlH}_{4} + 3 LiCl$

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When sodium metal is dissolved in liquid ammonia, a blue solution is formed. The blue colour is due to:

A.

solvated Na⁺ ions

B.

solvated electrons

C.

solvated ${NH}_{2}^{-}$ ions

D.

solvated protons

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Explanation

(b) $Na + (x + y) {NH}_{3} \overset{}{\to} {[Na {({NH}_{3})}_{x}]}^{+} + {[e {({NH}_{3})}_{y}]}^{-};$

This ammoniated electron is responsible for blue colour of solution, reducing nature and good conductor nature of solution.

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