NEET Practice Questions (MCQs) with Answers & Solutions

3-pentene-2-ol has two chiral carbon atoms, and each chiral carbon atom can have two different orientations (R or S). Therefore, the total number of stereoisomers is 2^2 = 4.

The most stable configuration of n-butane is the staggered-anti conformation, where the carbon atoms are arranged in a zig-zag pattern, minimizing the steric hindrance and maximizing the stability.

 (d) Alcohols show position isomerism; Ethers show metamerism; Alcohols and ethers show functional isomerism.         

(c) $$\begin{gathered} {\mathrm{CH}}_3-\underset{|}{\mathrm{C}}=\mathrm{CH}-{\mathrm{CH}}_2-{\mathrm{CH}}_3 \\ {\mathrm{CH}}_3 \end{gathered}$$ will not show cis-trans isomerism because double bonded carbon atom have two same groups (-CH₃, methyl group)

(d) Butane and isobutane and all higher alkanes show isomerism. 

(a) Acid has -COOH group whereas, ester has -COOR group.

(d) Pair of optical isomerism and geometrical isomerism are able to exhibit the phenomenon of stereoisomerism because both types of isomers differ only in their orientation in space.

(c) The conversion of $\mathrm{\alpha }$-glucose and $\mathrm{\beta }$-glucose is called mutarotation.

(d) A pair of d- l-optical isomers, i.e, enantiomer on mixing in equal moles gives racemic mixture.