NEET Practice Questions (MCQs) with Answers & Solutions

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The property by virtue of which a compound can turn the plane of polarization of light is known as:

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Explanation

(c) It is the definition of optical activity.

The molecular formula of a saturated compound is C2H4Br2.This formula permits the existence of:

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Explanation

(c) 1,1-dibromoethane and 1,2-dibromoethane.

How many isomers could be obtained from the alkane, C6H14?

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2-methylpent-3-ene is a chiral because it has:

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Explanation

2-methylpent-3-ene does not have a center or plane of symmetry. It has a chiral carbon (C2) due to the presence of four different groups attached to it, making the molecule chiral or optically active.

The (R)- and (S)-enantiomers of an optically active compound differ in

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Explanation

(c) R and S forms of an optically active compounds differ in their behaviour towards plane polarised light. The species which rotate the plane of polarised light toward right is called R-form (rectus form) or d-form (dextro-form) and the species which rotate the plane of polarised light towards left is known as S-form (sinister-form) or L-form (laevo-form).

The cylindrical shape of an alkyne is due to 

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Explanation

(d) In alkynes C≡C is present, in such bond one sigma and two Ï€ C-C bonds are present. Sigma bond is formed by sp-hybrid orbitals whereas Ï€-bonds are formed by unhybridised orbitals.

Hence, it shows cylindrical shape.

What is decreasing order of basicity of 1°, 2° and 3° ethyl amines and ammonia?          

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Explanation

(d) As the number of alkyl groups increases, the electron density on nitrogen atom also increases, so the basic character increases but 3° amines are less basic than 2° amines due to steric hindrance of 3° amines, so the correct order of basicity is

 Ammonia < 1 < 2 <3

 NH3<C2H5NH2<(C2H5)3N<(C2H5)2NH

The shortest C-C bond distance is found in               

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Explanation

(d) Acetylene has shortest C-C bond length because it has C≡C triple bond. The bond length follows the following order

   C-C>C=C>C≡C

Which of the following is more basic than aniline?                    

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Explanation

(d) Benzyl amine, C6H5CH2-N..H2 is more basic than aniline because benzyl group (C6H5CH2-) is electron donating group due to +I-effect. So, it is able to increase the electron density of N of -NH2 group. Thus, due to higher electron density, rate of donation of free pair of electron is increased, i.e. basic character is hhigher. Phenyl and nitro group are electron attractive groups, so they are able to decrease the electron density of N of -N..H2 group. Hence, they are less basic than aniline.

Which one of the following has the shortest carbon-carbon bond length?                      

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Explanation

(c) Ethyne (acetylene) have shortest C-C bond length because it has CC bond. The bond length follows the following order

       CC <C=C<C-C

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