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Which of the following reagents will be able to distinguish between 1-butyne and 2-butyne?

${NaNH}_{2}$

HCl

$O_{2}$

${Br}_{2}$

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Explanation

(a) ${NaNH}_{2}$ is used to distinguish between 1-butyne and 2-butyne.

${CH}_{3} {CH}_{2} C \equiv CH \overset{{NaNH}_{2}}{\to}$ ${CH}_{3} {CH}_{2} C \equiv CNa + \frac{1}{2} H_{2} ↑$

${CH}_{3} - C \equiv C - H \overset{{NaNH}_{2}}{\to}$ No reaction

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Which reagent distinguish propyne and propene?

Alkaline ${KMnO}_{4}$

${Cu}_{2} {Cl}_{2}$ + ${NH}_{4} Cl$

${Br}_{2}$ water

${Cu}_{2} {Cl}_{2}$ + ${NH}_{4} OH$

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Explanation

Propyne has acidic hydrogen and it reacts with ${Cu}_{2} {Cl}_{2}$ + ${NH}_{4} OH$ to form red ppt. Propene can not react.

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Which alkene has smallest heat of hydrogenation?

${CH}_{3} - CH = CH - {CH}_{3}$

${({CH}_{3})}_{2} C = CH - {CH}_{3}$

${CH}_{2} = CH - {CH}_{2} - {CH}_{3}$

${CH}_{3} - CH = CH - CH {({CH}_{3})}_{2}$

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Explanation

Higher is the stability of alkene, smaller is the heat of hydrogenation.

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The correct order of relatives rates of hydrogenation of alkenes is

Ethylene > propene > 2-butene > 2-methyl-2-butene

2-methyl-2-butene > 2-butene > Propene > Ethylene

2-butene > propene > ethylene > 2-methyl-2-butene

Propene > 2-butene > ethylene > 2-methyl-2-butene

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Explanation

Higher is the stability of alkane, smaller is the heat of hydrogenation.

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Which one of the following reaction is not possible?

CH₃COONa + HCI → CH₃COOH + NaCI

CH₃ –SO₃ H + H – C = C – Na → CH₃SONa + H – C = C – H

R – C = C – H + PhONa → PhOH + R – C = C – Na

H – C = C – H + NaH₂ → H – C = C – Na + NH₃

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Explanation

Stronger acid displaces weak acid from its salt.

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Which of the following is a correct statement regarding the relative acidic character of cyclopropane and propane?

Cyclopropane is more acidic than propane

Propane is more acidic than cyclopropane

Both are equally acidic

Bothe are neutral

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Explanation

C – H bond strength is less in cyclopropane.

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On halogenation, an alkane gives only one monohalogenated product. The alkane may be :

2-methyl butane

2, 2-dimethyl propane

cyclopentane

both (b) and (c)

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Which of the following compounds can be best prepared by Wurtz-reaction ?

Iso-butane

n-butane

n-pentane

Iso-pentane

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Explanation

(b) 2CH₃-CH₂-Cl $\to_{Dry ether}^{Na}$ CH₃-CH₂-CH₂-CH₃
Open chain alkane product having even number of carbons and symmetrical can be achieved by Wurtz reaction.

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${CH}_{3} Cl \overset{}{\to} {CH}_{4}$

Above conversion can be achieved by:

Zn/H⁺

LiAlH₄

Mg /(ether) then H₂O

all of these

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Ethane is subjected to combustion process. During the combustion the hybrid state of carbon changes from:-

sp² to sp³

sp³ to sp

sp to sp³

sp² to sp²

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Explanation

Δ
(b) CH₃-CH₃+7/2O₂→2CO₂+3H₂O
(sp³) (sp)

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