NEET Practice Questions (MCQs) with Answers & Solutions

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The vapour pressure of water depends upon:

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Explanation

The vapour pressure of water depends upon temperature only.

The boiling point of an azeotropic mixture of water and ethanol is less than that of water and ethanol. The mixture shows

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Explanation

Mixture of ethanol and water shows positive +ve deviation from Roult's law.

Mole of K2SO4 to be dissolved in 12 moles water to lower its vapour pressure by 10 mm of Hg at a temperature at which vapour pressure of pure water is 50 mm of Hg is

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Explanation

 

 

P-PsP=inin+N1050=3×n3×n+123n+12 = 15nn=1

Which has highest freezing point ?

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Explanation

Tf  is directly proportional to  number of ions

Lower is the effective molarity, higher is the freezing point.

Aluminium phosphate is 100% ionized in 0.01m aqueous solution. Hence, Tb/kb is

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Explanation

For AlPO4, i=2

TbKb=i × m =2×0.01=0.02

Which solution has highest freezing point?

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Explanation

Higher is the molar mass, lesser is the effective molarity. So, 1% sucrose solution has highest freezing point.

Osmotic pressure of 40% (w/V) urea solution is 1.64 atm. and that of 3.42% (w/V) cane sugar solution is 2.46 atm. When equal volumes of the above two solutions are mixed, the osmotic pressure of the resulting solution will be?  

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Explanation

π= π1+π2 , if equal volume are mixed volume of solution become double.

20g of naphthoic acid (C11H8O2) dissolved in 50g of benzene (Kf=1.72 K Kg mol-1) shows a depression in freezing point of 2K. The Vant Hoff factor is?

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Explanation

Mol. wt. of naphthoic acid=172

ΔTcal=1000 x 1.72 x 20 /50 x 172 = 4

i=experimentalΔTf=2/4=0.5
    calculated  ΔTf

A 0.002 molar solution of NaCl having degree of dissociation of 90% at 270C, has osmotic pressure equal to:-

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Explanation

α = i-1/n-1

0.9 = i-1/2-1

i=1.9

π=iCRT = 1.9x0.002x0.082x300

=0.094 bar

 

 

 

The density of NH4OH solution is found to be 0.6 g/ml. It contains 35% by mass of NH4OH. The normality of the solution is

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Explanation

dsol=    mass 
          volume

 

vsol= 100   ml
         0.6

 

N= W   X    1   
       E       V(L)

 

N= 35 1000 x 0.6 
        35          100

 

N = 6

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