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NEET NEET Questions — Free MCQ Practice

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S-S bond is present in

A.

H₂S₂O₇

B.

H₂SO₅

C.

H₂S₂O₈

D.

H₂S₂O₆

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Which is incorrectly given according to the order indicated?

A.

F₂>Cl₂>Br₂>I (Oxidizing power)

B.

HI>HBr>HCl>HF (Acidic Strength)

C.

F₂>Cl₂>Br₂>I₂ (Bond Energy)

D.

HF>HI>HBr>HCl (Boiling point)

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Explanation

The bond energy of F₂is less than Br₂due to interelectronic repulsion

Cl₂>Br₂>F₂>I₂

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Bleaching action of SO₂ is due to its

A.

acidic property

B.

basic property

C.

reducing property

D.

oxidising property

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Explanation

Bleaching action of: Bleaching by sulphur dioxide is due to the process of reduction in the presence of moisture.
$S O_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 [H]$ (nascent)

The nascent hydrogen liberated in the reaction is responsible for bleaching flower but when the flower comes in contact with air.

It get oxidized and be come coloured.

Colour material $+ [H] \to$ Colourless $a i r$ Colour

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The correct order of acidic strength of oxyacid of phosphorous is

A.

H₃PO₂> H₃PO₃>H₃PO₄

B.

H₃PO₄> H₃PO₃>H₃PO₂

C.

H₃PO₃>H₃PO₂>H₃PO₄

D.

H₃PO₂>H₃PO₄> H₃PO₃>

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Explanation

Acidity is directly proportional to free oxygen and inversely proportional to -OH group.

The double bonded oxygen has negative inductive effect (-I). And this electron withdrawing effect is experienced by one $H$ of the one $- O H$ group in $H_{3} P O_{2}$ . Hence it has greatest acidic strength.

Similarly, the -I effect of $O$ is experienced by two $H$ of the two $- O H$ groups in $H_{3} P O_{3}$ , hence electron withdrawing effect is reduced because it is getting distributed between two groups. Hence, it has lesser acidic strength. Similarly, in $H_{3} P O_{4}$ , it is distributed between 3 groups and so the acidic strength is least.

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Which is not hydrolysed with water?

A.

PCl₃

B.

NF₃

C.

NCl₃

D.

BCl₃

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Explanation

NF₃is not hydrolysed with water because N, as well as F, do not have vacant orbital.

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The following solid exists in the form of ions:-

A.

BI₃

B.

BCl₃

C.

BF₃

D.

CaBO₂

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Explanation

CaBO₂is calcium meta borate (Ca²⁺BO^-₂).

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Which of the following is not hydrolysed?

A.

CCl₄

B.

SiCl₄

C.

GeCl₄

D.

SnCl₄

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Explanation

hydrolysis of CCl₄ is not possible in ordinary conditions (absence of vacant orbitals)

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Correct order of boiling point of group 16 hydrides

A.

H₂O<H₂S<H₂Se<H₂Te

B.

H₂Te<H₂Se<H₂S<H₂O

C.

H₂S<H₂Se<H₂Te<H₂O

D.

H₂O<H₂Te<H₂Se<H₂S

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Explanation

H₂O has the highest boiling point due to the presence of hydrogen bonding.

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Ammonia on reaction with excess of chlorine gives

A.

NCl₃ and HCl

B.

N₂ and NH₄Cl

C.

NCl₃ and NH₄Cl

D.

N₂ and HCl

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Explanation

${NH}_{3} + \underset{(Excess)}{3 {Cl}_{2}} \to {NCl}_{3} + 3 HCl$

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White phosphorous reacts with calcium to form a certain compound which on hydrolysis produces

A.

PH₃

B.

H₃PO₄

C.

P₄O₆

D.

P₄O₁₀

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Explanation

When phosphorous reacts with calcium then calcium phosphide (Ca₃P₂) is formed ${Ca}_{3} P_{2} + 6 H_{2} O \to 3 Ca (OH)_{2} + 2 {PH}_{3}$

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