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The variation of the boiling point of the hydrogen halides is in the order HF > HI > HBr > HCl. What explains the higher boiling point of hydrogen fluoride?
Since, there is a strong hydrogen bonding between HF molecules. Hence, boiling point is highest for HF.
HF > HI > HBr > HI
Strong reducing behaviour of H3PO2 is due to
The strong reducing behavior of H3PO2 (phosphinic acid) is due to the presence of one -OH group and two P-H bonds. The P-H bonds are easily polarized, making the hydrogen atoms more acidic, which facilitates the release of electrons.
Acidity of diprotic acids in aqueous solutions increases in the order:-
(a) Acidic strength of hydrides increases as the size of central atom increases which weakens the M-H bond. Since, the size increases from S to Te thus acidic strength follows the order
H2S<H2Se<H2Te
Roasting of sulphides gives the gas X as a by-product. This is a colourless gas with choking smell of burnt sulphur and causes great damage to respiratory organs as a result of acid rain. Its aqueous solution is acidic acts as a reducing agent and its acid has never been isolated. The gas X is
(b) SO2 gas is obtained when any sulphide ore is roasted.
2M2S + 3O2 2M2O + 2SO2
This gas exhibits all the characteristics given in the question.
When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from
When Cl₂ gas reacts with hot and concentrated NaOH solution, chlorine undergoes disproportionation. Its oxidation states change from 0 to -1 (in NaOCl) and 0 to +5 (in NaClO₃). This disproportionation reaction is used in the manufacturing of bleaching powder.
Which of the following statements is not valid for oxoacids of phosphorus?
Sulphur trioxide can be obtained by which of the following reaction
(a) CaSO4 + CCaO + SO2 + CO
(b) Fe2(SO4)3 Fe2O3 + 3SO3
(c) S + 2H2SO4 3SO2 + 2H2O
(d) H2SO4 + PCl5 SO3HCl + POCl3 + HCl
chloro sulphonic acid
Thus, SO3 is obtained by heating Fe2(SO4)3
Among the following which is the strongest oxidising agent ?
Key Idea Element having higher tendency to get reduced or to accept an electron, is strong oxidising agent. Fluorine is the most electronegative element because electronegativity decreases on moving down the group. Hence, it gets reduced readily into F- ion and is a strongest oxidising agent.
The reaction of hydrogen and iodine monochloride is given as :
H2(g)+ 2ICl(g) 2HCl(g)+ I2(g)
This reaction is of first order with respect to H2(g) and 2ICl(g) following mechanisms were proposed:
Mechanism A:
H2(g)+ 2ICl(g) 2HCl(g)+ I2(g)
Mechanism B :
H2(g)+ ICl(g) HCl(g)+ HI(g) ; slow
HI(g)+ ICl(g) HClCg) + I2(g); fast
Which of the above mechanism (s) can be consistent with the given information about the reaction ?
Rate of reaction is always depends on slow reaction.
H2(g)+ 2ICl(g) 2HCl(g)+ I2(g) is first order reaction respect to H2 and I2 can be measured with the help of both mechanism A and B.
For which element would be a stable species :
(c) stable species.
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