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Which is the true covalent oxide of iodine?

$I_{2} O_{4}$

$I_{2} O_{5}$

$I_{2} O_{8}$

$I_{4} O_{9}$

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Explanation

higher the oxidation no, higher will be the covalent character .

$I_{2} O_{7} and I_{2} O_{9}$ do not exist

$I_{2} O_{4}$ is ionic in nature. It is infact iodyl iodate ${[I O]}^{+} {[I O_{3}]}^{-}$ . The only covalent oxide of iodine is $I_{2} O_{5}$

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$C l_{2} O$ is an anhydride of:

$H C l O_{4}$

HOCl

$C l_{2} O_{3}$

$H C l O_{2}$

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Explanation

2 HOCl - H₂O = Cl₂0

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Which of the following interhalogen anions is linear?

$I_{3}^{-}$

$I C l_{2}^{-}$

Both (a) and (b)

none of these

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The number of lone pairs of electrons present in central atom of $C I F_{3}$ are:

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Explanation

Cl has 7 valance electron and 3 is bonded ,so 4 electron is left. hence its 2 pair.

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The stability of interhalogens compounds follows the order:

$I F_{3} > B r F_{3} > C I F_{3}$

$B r F_{3} > I F_{3} > C l F_{3}$

$C l F_{3} > B r F_{3} > I F_{3}$

$C l F_{3} > I F_{3} > B r F_{3}$

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Explanation

stability of interhalogen comp directly proportional to diff of electronegativity

and inversely proportional to steric hindrance

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During bleaching of chlorine an antichlor is used to:

enhance bleaching action

eliminate hydrogen

remove chlorine from the fibre

liberate oxygen

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Explanation

An antichlor is a substance used to decompose residual hypochloride or chlorine after chlorine-based bleaching, in order to prevent ongoing reactions with, and therefore damage to, the material that has been bleached. Antichlors include sodium bisulfite, potassium bisulfite, sodium metabisulfite, sodium thiosulfate, and hydrogen peroxide.

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The bleaching action of bleaching powder is due to the formation of :

$O C l^{-}$

$O_{2}$

$C l_{2}$

$C l^{-}$

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Explanation

The bleaching powder has a strong bleaching action due to the formation of nascent oxygen.

When bleaching powder reacts with a small amount of acid, it gives nascent oxygen.

Thus, it acts as an oxidizing agent and thus acts as a bleaching agent.

2 C a O C l_{2} + H_{2} S O_{4} \to C a C l_{2} + C a S O_{4} + 2 H O C l

2 H O C l \to 2 H C l + 2 [O]

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Non-combustible hydride is:

$P H_{3}$

$A s H_{3}$

$S b H_{3}$

$N H_{3}$

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Explanation

because the temperature of the flame is usually lower than the ignition temperature of the ammonia–air mixture. The flammable range of ammonia in air is less than 16–25%.

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Which hydride possesses the maximum complex forming nature?

$N H_{3}$

$P H_{3}$

$B i H_{3}$

$S b H_{3}$

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Explanation

due to small size and high electron density , NH3 acts as ligands

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Which is least poisonous?

$N H_{3}$

$P H_{3}$

$A s H_{3}$

$S b H_{3}$

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Explanation

toxicity of hydride increase down the group

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