NEET Practice Questions (MCQs) with Answers & Solutions

(a) Only primary valencies are ionized .

[Co(NH₃)₅Br]SO₄$\stackrel{{\mathrm{BaCl}}_2}{\to }$[Co(NH₃)₅Br]²⁺ +BaSO₄

[Co(NH₃)₅SO₄]Br $\stackrel{{\mathrm{AgNO}}_3}{\to }$[Co(NH₃)₅SO₄]+AgBr

0.01mole of each by 0.01mole of reactants.

(c) Follow IUPAC rules.

(c) Prussian blue is Fe₄^III[Fe^II(CN)₆]₃ or M^IFe^III[Fe^II(CN)₆, where M^I is Na,K,Rb,Li,Cs

(c) Follows IUPAC rules.

(d) Magnetic moment($\mathrm{\mu }$)=$\sqrt{\mathrm{n}(\mathrm{n}+2} \mathrm{BM}$

or 3.83=$\sqrt{\mathrm{n}(\mathrm{n}+2}$

or 3.83x 3.83= n²+2n

14.6689=n²+2n

n=3

Hence , number of unpaired electron in d-subshell of penultimate shell of chromium (Cr=24)=3

so the configuration of chromium ion is Cr3+=1s²,2s²2p⁶,3s²3p⁶3d³

In [Cr(H2O)₆]Cl₂, oxidation state of Cr is +3. Hence, in 3d³ the distribution of electrons 3d¹_xy,3d¹_yz,3d¹_zx,3d⁰_x²-y²,3d⁰_z²

[NiCl₄]^2-$\Rightarrow$Tetrahedral(sp³)

[PtCl₄]^2- $\Rightarrow$ Square planar(dsp²)

[Zn(NH₃)₂Cl₂] does not show geometrical isomerism due to Sp³ hybridisation

only [Pt(NH₃)₂Cl₂] shows geometrical isomerism.

Grignard reagent is a $\mathrm{\sigma }$ complex

In ferrocene (Fe(C5H5)2), the iron atom is sandwiched between two cyclopentadienyl (C5H5-) rings. Each cyclopentadienyl ring acts as a bidentate ligand, contributing two electrons to the iron atom. Therefore, the coordination number of iron in ferrocene is 10.