NEET Practice Questions (MCQs) with Answers & Solutions

Assertion : The magnitude of charge density for a given ligand increases as the charge on the metal

                  ion increases.

Reason : ${\mathrm{NH}}_3$ is a weak field ligand towards ${\mathrm{Co}}^{2+}$ but acts as a strong field ligand towards ${\mathrm{Co}}^{3+}.$

Addition of Br₂ on cis-butene-2 gives:

In ${\mathrm{S}}_{{\mathrm{N}}^2}$ reactions, the correct order of reactivity for the following compounds : ${\mathrm{CH}}_3\mathrm{Cl}$, ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$, ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$ and ${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$ is :

X $\stackrel{{\mathrm{Cl}}_2}{\to }$ Benzotrichloride $\stackrel{\mathrm{Hydrolysis}}{\to }$ Y

X and Y respectievely are:

Benzene on reaction with a mixture of HNO₃ and H₂SO₄ followed by reaction of Cl₂/FeCl₃ gives:

In the following sequences of reactions;

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{I}\stackrel{\mathrm{KOH}(\mathrm{alc}.)}{\to }$(A)$\stackrel{{\mathrm{Br}}_2}{\to }$(B)$\stackrel{{\mathrm{NaNH}}_2/{\mathrm{NH}}_3}{\to }$(C)

the end product (C) is:

Friedel-Craft's reaction of bromobenzene with methyl iodide gives:

Benzyl chloride (C₆H₅CH₂Cl) can be prepared from toluene by chlorination with:

Elimination of HBr from 2-bromobutane results in the formation of:

(CH₃)₃CMgCl on reaction with D₂O gives: