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NEET Practice Questions (MCQs) with Answers & Solutions

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The alkyl halide is converted into an alcohol by

addition

substitution

dehydrohalogenation

elimination

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Explanation

(b) RCl + NaOH(aq) $\to$ ROH + NaCl

It is an example of nucleophilic substitution reaction.

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Glycerol on warming with excess of HI:

2-iodopropane

1-iodopropane

1,2,3-tri-iodopropane

none of the above

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Dehydrogenation of 2-butanol gives:

2-butene

butanone

butyraldehyde

1-butene

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Explanation

(b) CH₃CH₂CH(OH)CH₃ $\to_{- H_{2}}^{Cu, ∆}$ CH₃CH₂COCH₃

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Which of the following has lowest boiling point?

Phenol

o-nitrophenol

m-nitrophenol

p-nitrophenol

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Explanation

(b) o-nitrophenol has intramolecular H-bonding.

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Oxidation of 2-propanol by K₂Cr₂O₇ and dilute H₂SO₄ leads to the formation of:

propanal

propanoic acid

methanoic acid

propanone

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A compound X with molecular formula C₃H₈O can be oxidised to a compound Y with the molecular formula C₃H₆O₂. X is most likely to be:

primary alcohol

secondary alcohol

aldehyde

ketone

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Explanation

The formula represents for alcohol. Also, secondary alcohol gives acid with less no. of carbon atoms.

CH₃CH₂CH₂OH $\overset{[O]}{\to}$ CH₃CH₂CHO $\to$ CH₃CH₂COOH

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The ionisation constant of phenol is higher than that of ethanol because

phenoxide ion is bulkier than ethoxide

phenoxide ion is stronger base than ethoxide

phenoxide ion is stabilised through delocalisation

phenoxide ion is less stable than ethoxide

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Explanation

The ionization constant of phenol is higher than that of ethanol because the phenoxide ion is stabilized through delocalization of the negative charge over the benzene ring. This delocalization of the negative charge makes the phenoxide ion more stable and a weaker base.

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Which one among the following is Williamson's synthesis?

${}_{{CH}_{3}}^{{CH}_{3}}> C = O \to_{conc . HCl}^{Zn - Hg}$ CH₃-CH₂-CH₃

CH₃-CHO $\to_{- H_{2} O}^{Dil . NaOH}$ CH₃-CH=CH-CHO

C₂H₅I + C₂H₅ONa $\to$ C₂H₅.O.C₂H₅ + NaI

HCHO $\overset{NaOH}{\to}$ HCOONa + CH₃OH

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Explanation

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An organic compound A reacts with PCl₅ to give B. The compound B with sodium metal gives n-butane. Thus, A and B are:

C₂H₅OH and C₂H₅Cl

C₂H₅Cl and C₂H₅ONa

C₃H₇OH and CH₃CH₂CH₂OCl

C₄H₉OH and C₄H₉OCl

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Explanation

(a) C₂H₅OH $\overset{{PCl}_{5}}{\to}$ C₂H₅Cl $\to_{Wurtz reaction}^{Na}$ C₂H₅C₂H₅

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The boiling point of p-nitrophenol is higher than that of o-nitrophenol because

NO₂group at p-position behaves in a different way from that at o-position

intramolecular hydrogen bonding exists in p-nitrophenol

there is intermolecular hydrogen bonding in p-nitrophenol

p-nitrophenol has a higher molecular weight than o-nitrophenol

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Explanation

The boiling point of p-nitrophenol is higher than that of o-nitrophenol because in p-nitrophenol, intermolecular hydrogen bonding occurs between the hydrogen of the -OH group and the oxygen of the -NO2 group. This intermolecular hydrogen bonding increases the strength of the intermolecular forces, resulting in a higher boiling point.

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