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All Physics Chemistry Botany Zoology

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Evolution is not

A. a stochastic process B. Based on chance events in nature C. Based on chance mutation in the organisms D. Directed process in the sense of determinsm

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Explanation

NCERT page number 132, Para-2

7.3 What Are The Evidences For Evolution?

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Which of the following statements is not true if we consider postulates of Darwinian theory of evolution?

A. Evolution by natural selection would have started when cellular forms of life with similarities in metabolic capabilities originated on Earth B. The rate of appearance of new forms is linked to the life cycle or the life span. C. Fitness is based on characteristics which are inherited. D. Adaptive ability is inherited.

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Explanation

NCERT page number 134

7.5 Biological Evolution, Para 1 and 2

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Fitness is not

A. Something for which nature selects B. End result of the ability to adapt and get selected by nature C. Based on characteristics which are inherited D. Considered when cellular forms of life were originated.

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Explanation

NCERT page number 134

7.5 Biological Evolution, Para 2

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Two peaks will be observed in which of the operation of natural selection?

A. Disruptive B. Directional C. Stabilising D. Both A and B

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Explanation

NCERT page number 136

Figure 7.8 ©

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Peak getting higher and narrower is observed in which of the operation of natural selection?

A. Disruptive B. Directional C. Stabilising D. Both A and B

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Explanation

NCERT page number 136

Figure 7.8 (a)

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What will be the frequency of homozygote dominant in a population of triploid organisms.

A. p×p×p B. AA C. p D. P

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Explanation

NCERT page number 137, para-1

7.7 Hardy-Weinberg Equilibrium

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If the population of a place has a certain character which is recessive in as many as 100 individuals. Find the value of q if total number of individuals are 1000

A. 0.1 B. 0.7 C. 0.3 D. 1

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Explanation

q2=100/1000

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If 900 people make a population such that 300 are albino. Calculate the frequency of carriers?

A. 42 B. 44 C. 48 D. 49

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Explanation

q2=300/900. Calculate q from there.

p+q=1 calculate p from there

Now carriers will be 2pq.

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If p=0.8 calculate q

A. 0.8 B. 0.2 C. 6.4 D. 0.4

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Explanation

p+q=1

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If a population has dominant phenotype in 1600 individuals out of 2000 then calculate the frequency of heterozygote.

A. 494 B. 256 C. 128 D. 356

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Explanation

dominant phenotype means 2pq+p2

Rest is same q2= 400/2000

p+q=1 calculate p from there

Now carriers will be 2pq.

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