Consider a case where light travels from medium 1 to medium 2. If the speed of light in medium 2 ($v_2$) is less than the speed of light in medium 1 ($v_1$), what can be concluded about the angle of refraction ($r$) relative to the angle of incidence ($i$)?
The NCERT text (Wave Optics, page 259) states: 'From the above equation, we get the important result that if $r < i$ (i.e., if the ray bends toward the normal), the speed of the light wave in the second medium ($v_2$) will be less then the speed of the light wave in the first medium ($v_1$).' This is a direct consequence of Snell's law $n_1 \sin i = n_2 \sin r$ and $n = c/v$, which implies $ \frac{\sin i}{\sin r} = \frac{n_2}{n_1} = \frac{v_1}{v_2} $. If $v_2 < v_1$, then $ \frac{v_1}{v_2} > 1 $, so $ \frac{\sin i}{\sin r} > 1 $, which means $\sin i > \sin r$, and thus $i > r$ (for acute angles).