NEET Practice Questions (MCQs) with Answers & Solutions

While not explicitly stated in the provided text for a bar magnet, the property of magnetic field lines emerging from one face and entering another is stated for a solenoid: 'The field lines remain continuous, emerging from one face of the solenoid and entering into the other face.' By analogy and general magnetic principles (which candidates for NEET are expected to know), magnetic field lines emerge from the North pole and enter the South pole outside a magnet. The provided context about iron filings also implies this pattern.

The NCERT text states: 'In Fig. 4.15(b), we see that the field at the interior mid-point P is uniform, strong and along the axis of the solenoid.' This directly supports option 2.

The NCERT text explicitly states: 'The magnetic field lines do not intersect, for if they did, the direction of the magnetic field would not be unique at the point of intersection.' Options 1, 2, and 4 are all stated as properties of magnetic field lines.

The NCERT text provides: 'In particular, we can write down the equatorial field ($B_E$) of a bar magnet at a distance r, for $r >> l$, where l is the size of the magnet: $B_E = -\frac{\mu_0}{4\pi} \frac{m}{r^3}$ (5.4).' This matches option 2.

The NCERT text states: 'Comparison of Eqs. (5.1), (5.2) and (5.3) with the corresponding equations for electric dipole (Chapter 1), suggests that magnetic field at large distances due to a bar magnet of magnetic moment m can be obtained from the equation for electric field due to an electric dipole of dipole moment p, by making the following replacements: $\vec{E} \to \vec{B}$, $\vec{p} \to \vec{m}$, $\frac{1}{4\pi\epsilon_0} \to \frac{\mu_0}{4\pi}$'. This set of replacements is correctly reflected in option 3.

The NCERT text says: 'In Fig. 4.15(a), it is clear from the circular loops that the field between two neighbouring turns vanishes.' This directly supports option 2.

The NCERT text states: 'The torque on the needle is [see Eq. (4.23)], $\vec{\tau} = \vec{m} \times \vec{B}$ (5.2). In magnitude $\tau = mB \sin\theta$. Here $\tau$ is restoring torque and $\theta$ is the angle between $m$ and $B$.' Since a solenoid acts as a bar magnet, this applies to the equivalent solenoid as well. Therefore, $\theta$ is the angle between the magnetic moment ($m$) and the magnetic field ($B$). This aligns with option 3.

The context states: 'Substances like glucose, amino acids, Na+, etc., in the filtrate are reabsorbed actively…'. Nitrogenous wastes are absorbed by passive transport, and H+, K+, and ammonia are secreted, not primarily reabsorbed actively in bulk.

The passage highlights: 'A comparison of the volume of the filtrate formed per day (180 litres per day) with that of the urine released (1.5 litres), suggest that nearly 99 per cent of the filtrate has to be reabsorbed by the renal tubules.'

The text states: 'Proximal Convoluted Tubule (PCT): PCT is lined by simple cuboidal brush border epithelium which increases the surface area for reabsorption. Nearly all of the essential nutrients, and 70-80 per cent of electrolytes and water are reabsorbed by this segment.'