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What type of mutation results from a change in a single base pair of DNA?
According to the NCERT text: 'mutation also arise due to change in a single base pair of DNA. This is known as point mutation.'
Sickle cell anemia is a classical example of which type of mutation?
The NCERT text explicitly states: 'A classical example of such a mutation is sickle cell anemia', referring to point mutation from the previous sentence.
Deletions and insertions of base pairs of DNA are responsible for causing which type of mutation?
The NCERT text mentions: 'Deletions and insertions of base pairs of DNA, causes frame-shift mutations'.
What are chemical and physical factors that induce mutations collectively referred to as?
The NCERT text states: 'However, there are many chemical and physical factors that induce mutations. These are referred to as mutagens.'
Which of the following is an example of a physical mutagen mentioned in the context?
The context provides: 'UV radiations can cause mutations in organisms – it is a mutagen.' This identifies UV radiation as a physical mutagen.
Mutation leads to changes in which of the following aspects of an organism?
The NCERT text defines mutation as: 'a phenomenon which results in alteration of DNA sequences and consequently results in changes in the genotype and the phenotype of an organism.'
The loss or gain of a segment of DNA leads to an alteration in chromosomes. These chromosomal alterations are also known as:
The text states: 'Therefore loss (deletions) or gain (insertion/duplication) of a segment of DNA, result in alteration in chromosomes. Since genes are known to be located on chromosomes, alteration in chromosomes results in abnormalities or aberrations. Chromosomal aberrations are commonly observed in cancer cells.'
Which of the following describes the relationship between the stopping distance ($d_s$) of a vehicle and its initial velocity ($v_0$) when brakes are applied with a constant deceleration ($a$)?
According to the provided text and the derived expression in Example 2.6, the stopping distance is given by $d_s = \frac{-v_0^2}{2a}$. This shows that the stopping distance is proportional to the square of the initial velocity ($v_0^2$). The context explicitly states, 'Thus, the stopping distance is proportional to the square of the initial velocity.'
A car's initial velocity is $10 \text{ m/s}$, and its stopping distance is $x$. If the initial velocity of the car is increased to $20 \text{ m/s}$ (doubled), what will be its new stopping distance, assuming the same deceleration capacity?
The context states, 'Doubling the initial velocity increases the stopping distance by a factor of 4 (for the same deceleration).' This is because stopping distance ($d_s$) is proportional to the square of the initial velocity ($v_0^2$). If $v_0$ becomes $2v_0$, then $d_s'$ will be proportional to $(2v_0)^2 = 4v_0^2$, making the new stopping distance $4x$.
Reaction time is best described as the:
Example 2.7 clearly defines reaction time: 'Reaction time is the time a person takes to observe, think and act.' It encompasses the entire cognitive and motor process from stimulus recognition to initial response.
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.