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If the angle of incidence for a ray of light traveling from a denser to a rarer medium is greater than the critical angle, what phenomenon occurs?

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Explanation

The NCERT text states, 'For values of i larger than ic, Snell’s law of refraction cannot be satisfied, and hence no refraction is possible.' In this case, 'the incident ray is totally reflected. This is called total internal reflection.'

Which of the following is NOT an application or example of total internal reflection?

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Explanation

The NCERT summary lists 'Multiple internal reflections in diamond ($i_c \approx 24.4^\circ$), totally reflecting prisms and mirage, are some examples of total internal reflection.' Optical fibres are also stated to make use of total internal reflection. Rainbow formation primarily involves dispersion and refraction, not total internal reflection in its primary mechanism.

In an optical fibre, how does the refractive index of the core compare to that of the cladding?

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Explanation

The NCERT text states, 'Each fibre consists of a core and cladding. The refractive index of the material of the core is higher than that of the cladding.' This ensures that light entering the core undergoes total internal reflection at the core-cladding interface.

Which statement best describes the intensity of a totally internally reflected ray compared to the incident ray?

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Explanation

The NCERT text explains, 'When light gets reflected by a surface, normally some fraction of it gets transmitted. The reflected ray, therefore, is always less intense than the incident ray, howsoever smooth the reflecting surface may be. In total internal reflection, on the other hand, no transmission of light takes place.' This implies that the intensity of the totally internally reflected ray is essentially the same as the incident ray, as there is no loss due to transmission.

For total internal reflection to occur, the refractive index of the denser medium ($n_1$) relative to the rarer medium ($n_2$) must satisfy which condition, given the critical angle $i_c$?

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Explanation

From Snell's law, $\sin i_c / \sin 90^\circ = n_2 / n_1$. Since $n_{12}$ is the refractive index of medium 1 with respect to medium 2, $n_{12} = n_1/n_2$. Therefore, $\sin i_c = n_2/n_1 = 1/n_{12}$, which means $n_{12} = 1/\sin i_c$. The NCERT text also states 'The refractive index of denser medium 1 with respect to rarer medium 2 will be $n_{12} = 1/\sin i_c$.'

The refractive index of turpentine is less than that of water, but its optical density is higher. What does 'optically denser' primarily refer to in this context?

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Explanation

The NCERT text clarifies, 'Optical density should not be confused with mass density, which is mass per unit volume. It is possible that mass density of an optically denser medium may be less than that of an optically rarer medium... optical density is the ratio of the speed of light in two media.'

Which of the following phenomena is demonstrated when a laser beam directed from below a beaker of turbid water strikes the upper water surface obliquely, and the light is observed to be totally reflected back into the water, with no light emerging into the air?

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Explanation

The NCERT text describes this exact experiment: 'Adjust the direction of laser beam until you find the angle for which the refraction above the water surface is totally absent and the beam is totally reflected back to water. This is total internal reflection at its simplest.'

What happens to the wavelength and speed of propagation when a wave gets refracted into a denser medium?

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Explanation

The NCERT text says, 'The above equation implies that when a wave gets refracted into a denser medium ($v_1 > v_2$) the wavelength and the speed of propagation decrease but the frequency $\nu$ (= v/$\lambda$) remains the same.' This is relevant because total internal reflection involves refraction principles before the critical angle is reached.

When does Snell's law of refraction cease to be satisfied, leading to total internal reflection?

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Explanation

The NCERT text explicitly states, 'For values of $i$ larger than $i_c$, Snell’s law of refraction cannot be satisfied, and hence no refraction is possible.'

In an n-type silicon semiconductor, the donor energy level ($E_D$) is located:

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Explanation

According to the NCERT text, 'In the energy band diagram of n-type Si semiconductor, the donor energy level $E_D$ is slightly below the bottom $E_C$ of the conduction band and electrons from this level move into the conduction band with very small supply of energy.'

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