NEET Practice Questions (MCQs) with Answers & Solutions

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NEET 2025

If the half-life $(t_{1/2})$ for a first order reaction is 1 minute, then the time required for 99.9% completion of the reaction is closest to:

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Explanation

99.9% completion leaves $1/1000$ remaining. $\left(\tfrac12\right)^n = \tfrac{1}{1000}\Rightarrow n\approx10$ half-lives $= 10$ minutes.

NEET 2025

The correct order of the wavelength of light absorbed by the following complexes is: A. $[\text{Co(NH}_3)_6]^{3+}$, B. $[\text{Co(CN)}_6]^{3-}$, C. $[\text{Cu(H}_2\text{O)}_4]^{2+}$, D. $[\text{Ti(H}_2\text{O)}_6]^{3+}$. Choose the correct answer:

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Explanation

Larger crystal-field splitting $\Delta$ means shorter absorbed wavelength. $\Delta$: B (CN⁻) > A (NH₃) > D (Ti³⁺/H₂O) > C (Cu²⁺/H₂O). So wavelength increases as B < A < D < C.

NEET 2025

Which one of the following compounds can exist as cis-trans isomers?

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Explanation

1,2-Dimethylcyclohexane has two different groups on each of two ring carbons → cis and trans isomers exist. The others lack the required geometric restriction.

NEET 2025

Phosphoric acid ionizes in three steps with their ionization constant values $K_{a_1}$, $K_{a_2}$ and $K_{a_3}$, respectively, while K is the overall ionization constant. Which of the following statements are true? A. $\log K = \log K_{a_1} + \log K_{a_2} + \log K_{a_3}$. B. $\text{H}_3\text{PO}_4$ is a stronger acid than $\text{H}_2\text{PO}_4^-$ and $\text{HPO}_4^{2-}$. C. $K_{a_1} > K_{a_2} > K_{a_3}$. D. $K_{a_1} = \dfrac{K_{a_3}+K_{a_2}}{2}$. Choose the correct answer:

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Explanation

$K = K_{a_1}K_{a_2}K_{a_3}\Rightarrow\log K = \sum\log K_{a_i}$ (A true). Successive ionization weakens: $K_{a_1} > K_{a_2} > K_{a_3}$ (C true) and $\text{H}_3\text{PO}_4$ is the strongest (B true). D is false.

NEET 2025

Which one of the following reactions does NOT give benzene as the product?

COONa(1) PhCOONa + sodalime, Δ(2) n-hexane / Mo₂O₃, 773 K(3) HC≡CH / red-hot Fe, 873 KN₂⁺Cl⁻(4) PhN₂⁺Cl⁻ + H₂O, warm
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Explanation

Benzene diazonium chloride with warm water gives phenol (and N₂), not benzene. The other three (decarboxylation, aromatization of hexane, cyclic trimerization of ethyne) all give benzene.

NEET 2025

If the molar conductivity $(\Lambda_m)$ of a $0.050\ \text{mol L}^{-1}$ solution of a monobasic weak acid is $90\ \text{S cm}^2\text{mol}^{-1}$, its extent (degree) of dissociation will be [Assume $\Lambda^\circ_+ = 349.6\ \text{S cm}^2\text{mol}^{-1}$ and $\Lambda^\circ_- = 50.4\ \text{S cm}^2\text{mol}^{-1}$]:

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Explanation

$\Lambda^\circ_m = 349.6 + 50.4 = 400$. $\alpha = \dfrac{\Lambda_m}{\Lambda^\circ_m} = \dfrac{90}{400} = 0.225$.

NEET 2025

Given below are two statements:

Statement I: A hypothetical diatomic molecule with bond order zero is quite stable.

Statement II: As bond order increases, the bond length increases.

In the light of the above statements, choose the most appropriate answer:

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Explanation

Bond order zero means the molecule does not exist / is unstable (I false). Bond length decreases (not increases) with increasing bond order (II false).

NEET 2025

Out of the following complex compounds, which of the compound will be having the minimum conductance in solution?

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Explanation

$[\text{Co(NH}_3)_3\text{Cl}_3]$ is a non-electrolyte (no ions in solution), so it has the minimum conductance.

NEET 2025

Match List-I with List-II:

List-I — A. $\text{XeO}_3$, B. $\text{XeF}_2$, C. $\text{XeOF}_4$, D. $\text{XeF}_6$

List-II — I. $sp^3d$; linear, II. $sp^3$; pyramidal, III. $sp^3d^3$; distorted octahedral, IV. $sp^3d^2$; square pyramidal

Choose the correct answer:

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Explanation

$\text{XeO}_3$: $sp^3$ pyramidal (II); $\text{XeF}_2$: $sp^3d$ linear (I); $\text{XeOF}_4$: $sp^3d^2$ square pyramidal (IV); $\text{XeF}_6$: $sp^3d^3$ distorted octahedral (III).

NEET 2025

$\text{C(s)} + 2\text{H}_2\text{(g)} \to \text{CH}_4\text{(g)}$; $\Delta H = -74.8\ \text{kJ mol}^{-1}$. Which of the following diagrams gives an accurate representation of the above reaction? [R → reactants; P → products]

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Explanation

$\Delta H$ is negative (exothermic), so the products lie below the reactants by 74.8 kJ mol⁻¹, with an activation hump in between.

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