Nucleon is common name for
$ { volume of atom \over volume of nuclear } = {4\pi \lambda l_1^3 \over 4/ 3 \pi \lambda 1_2^3 } = {(10^{-10})^3 \over (10^{-15})^3 }= 10^{15} $
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Nucleon is common name for
$ { volume of atom \over volume of nuclear } = {4\pi \lambda l_1^3 \over 4/ 3 \pi \lambda 1_2^3 } = {(10^{-10})^3 \over (10^{-15})^3 }= 10^{15} $
The nucler $_7N^{14}$ and $_6C^{13}$ can be described as
The nuclei $_7N^{14}$ and $_6C^{13}$ have the same number of neutrons (7). Nuclei with the same number of neutrons but different numbers of protons are called isotones.
Plutonium decays with half life time 24000 year. if Plutonium is stored after 72000 yes, the fraction of it that remain
To find the fraction of Plutonium remaining after 72000 years, we need to determine how many half-lives have passed. The half-life of Plutonium is 24000 years. After 72000 years, the number of half-lives is:\[ \frac{72000}{24000} = 3 \] The fraction remaining after 3 half-lives is:\[ \left( \frac{1}{2} \right)^3 = \frac{1}{8} \] Therefore, the correct answer is \( \frac{1}{8} \).
The radio of minimum to maximum wave length in Balmer series is
$ {N \over N0} = ( {1\over 2} ) ^ {t /T1/2} = ({ 1 \over2}) {72000 \over 24000} = {1 \over 8} $
$_6C^{12}$ absorbs an energetic neutron and emits a $\beta$ Particle. The resulting nucleus is
A value & Z value $ _{36}Kr ^{89}$
two deutrons each of mass m fuse to form helium resulting in release of energy E the mass of helium formed is
$ _6Cl^2 + _0n^1 \rightarrow N_7^{13} + e_{-1} ^0$
What percent of original radio active substans is left after 5 half life time
$ E = (\triangle m)C^2$ $ E = (2m-M) C^2$ ${ E \over C^2} = 2m-M$ $ M = 2m - {E/C^2}$
In which region of electro magnetic spectum does the Lyman series of hydrogen atom like
$at \,t = 0 \; \;\; N =No$ $ t = T_ {1/2} \times 1 \;\;\; N = No/2 \;\;\; \therefore {N \over No} = {1 \over 16}$ $ t = T_ {1/2} \times 2 ;;; N = No/4 ;;; {N\over No} \times 100 = { 1 \over 32 } \times 100$ $ t = T_ {1/2} \times 3 \;\;\; N = No/8 \;\;\; =3.125 $ $ t = T_ {1/2} \times 4 \;\;\; N = No/16 \;\;\; \approx 3 \%$ $ t = T_ {1/2} \times 5 \;\;\; N = No/32 $
In terms of Rydergi constant R. The wave number of first Balmer line is
The hydrogen atom can give spectral lines in the series Lyman, Balmer and Paschen.which of the following statement is correct
$ wave number = {1 \over \lambda} = R [{1 \over 2^2} - {1 \over 3^2}] = R[{1\over 4} - {1 \over 9}] = { 5R \over 36 }$
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