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Find the value of r if I = 1 A and potential difference across PQ is 1V
Vsq=i3×1+rI3
where Vsq=26/
Therefore, r = 25Ω
A T.V tower has a height of 80 m. The maximum distance up to which T.V transmission can be received is equal to . ---------(radius of earth = $ 6.4 \times 10 ^ 6 m)$
A receiving station on the ground is receiving a signal of frequency 10 MHz, then the mode of transmission is
On a particular day, the maximum frequency reflected from the ionosphere is 8 MHz. On another day it was found to increase to 9 MHz. The ratio of the minimum electron densities of ionosphere on the two days is
Consider an optical communication system operating at $\lambda = 800 nm$ . Suppose only 1% of the optical source frequency is the available channel bandwidth for optical communication. No. of channels that can be accomodated for transmitting video T.V signals requiring an approximate band width of 4.5 MHz is
A transmitting antenna at the top of a tower has a height of 50m and the height of the receiving antenna is 32m. The maximum distance between them for satisfactory communication in line of right mode is______ .Given radios of earth R = 6400 km
The characteristic impedence of a co-axial cable is between
The relation between the maximum electron denisity N max and the critical frequency f for the ionosphere can be given as
Two paper screens A and B are separated by distance 100 m. A bullet penetrates A and B, at points P and Q respectively, where Q is 10 cm below P. If bullet is travelling horizontally at the time of hitting A, the velocity of bullet at A is nearly
It is a case of horizontal projectile.
So, ax = 0, ux = 4, uy = 0, ay = –g
R = 100m,
T=root(2H/g)
R = ux T
FROM HERE SOLVE FOR Ux
A transmitter transmit a power of 10 kw when modulation is 50%. What is the power of carrier wave ?
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.